###### UGC NET CS 2018-DEC Paper-2

October 5, 2023###### UGC NET CS 2018-DEC Paper-2

October 5, 2023# UGC NET CS 2018-DEC Paper-2

Question 12 |

If the frame buffer has 10-bits per pixel and 8-bits are allocated for each of the R,G and B components then what would be the size of the color lookup table(LUT)

(2 ^{10} +2^{ 11} ) bytes | |

(2 ^{10} +2^{ 8} ) bytes | |

(2 ^{10} + 2^{ 24} ) bytes | |

(2 ^{8} + 2^{ 9} ) bytes |

Question 12 Explanation:

10-bits per pixel it means we will have 2

8-bits are allocated for each of the R,G and B components, means each entry in color lookup table is of 24-bits( 8-bits for each of the R, G and B component).

24-bits = 3 Bytes

So the size of lookup table is = Number of entries * size of each entry

So the size of lookup table is = (2

the size of lookup table is = 3072 Bytes = (2

^{ 10} entries in color lookup table.8-bits are allocated for each of the R,G and B components, means each entry in color lookup table is of 24-bits( 8-bits for each of the R, G and B component).

24-bits = 3 Bytes

So the size of lookup table is = Number of entries * size of each entry

So the size of lookup table is = (2

^{ 10} * 3) Bytesthe size of lookup table is = 3072 Bytes = (2

^{10} + 2^{ 11} ) BytesCorrect Answer: A

Question 12 Explanation:

10-bits per pixel it means we will have 2

8-bits are allocated for each of the R,G and B components, means each entry in color lookup table is of 24-bits( 8-bits for each of the R, G and B component).

24-bits = 3 Bytes

So the size of lookup table is = Number of entries * size of each entry

So the size of lookup table is = (2

the size of lookup table is = 3072 Bytes = (2

^{ 10} entries in color lookup table.8-bits are allocated for each of the R,G and B components, means each entry in color lookup table is of 24-bits( 8-bits for each of the R, G and B component).

24-bits = 3 Bytes

So the size of lookup table is = Number of entries * size of each entry

So the size of lookup table is = (2

^{ 10} * 3) Bytesthe size of lookup table is = 3072 Bytes = (2

^{10} + 2^{ 11} ) Bytes Subscribe

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