UGC NET CS 2018-DEC Paper-2

Question 12

If the frame buffer has 10-bits per pixel and 8-bits are allocated for each of the R,G and B components then what would be the size of the color lookup table(LUT)

A	(2 ¹⁰ +2¹¹ ) bytes
B	(2 ¹⁰ +2⁸ ) bytes
C	(2 ¹⁰ + 2²⁴ ) bytes
D	(2 ⁸ + 2⁹ ) bytes

Computer-GraphicsLUT

Question 12 Explanation:

10-bits per pixel it means we will have 2¹⁰ entries in color lookup table.
8-bits are allocated for each of the R,G and B components, means each entry in color lookup table is of 24-bits( 8-bits for each of the R, G and B component).
24-bits = 3 Bytes
So the size of lookup table is = Number of entries * size of each entry
So the size of lookup table is = (2¹⁰ * 3) Bytes
the size of lookup table is = 3072 Bytes = (2 ¹⁰ + 2¹¹ ) Bytes

Correct Answer: A

Question 12 Explanation:

10-bits per pixel it means we will have 2¹⁰ entries in color lookup table.
8-bits are allocated for each of the R,G and B components, means each entry in color lookup table is of 24-bits( 8-bits for each of the R, G and B component).
24-bits = 3 Bytes
So the size of lookup table is = Number of entries * size of each entry
So the size of lookup table is = (2¹⁰ * 3) Bytes
the size of lookup table is = 3072 Bytes = (2 ¹⁰ + 2¹¹ ) Bytes