October 5, 2023
October 5, 2023
October 5, 2023
UGC NET CS 2018-DEC Paper-2
October 5, 2023
 Question 12
​If the frame buffer has 10-bits per pixel and 8-bits are allocated for each of the R,G and B components then what would be the size of the color lookup table(LUT)
 A (2​ 10​ +2​ 11​ ) bytes B (2​ 10​ +2​ 8​ ) bytes C (2​ 10​ + 2​ 24​ ) bytes D (2​ 8​ + 2​ 9​ ) bytes
Question 12 Explanation:
10-bits per pixel it means we will have 2​ 10 ​ entries in color lookup table.
8-bits are allocated for each of the R,G and B components, means each entry in color lookup table is of 24-bits( 8-bits for each of the R, G and B component).
24-bits = 3 Bytes
So the size of lookup table is = Number of entries * size of each entry
So the size of lookup table is = (2​ 10​ * 3) Bytes
the size of lookup table is = 3072 Bytes = (2​ 10​ + 2​ 11​ ) Bytes
Question 12 Explanation:
10-bits per pixel it means we will have 2​ 10 ​ entries in color lookup table.
8-bits are allocated for each of the R,G and B components, means each entry in color lookup table is of 24-bits( 8-bits for each of the R, G and B component).
24-bits = 3 Bytes
So the size of lookup table is = Number of entries * size of each entry
So the size of lookup table is = (2​ 10​ * 3) Bytes
the size of lookup table is = 3072 Bytes = (2​ 10​ + 2​ 11​ ) Bytes