Computer-Networks
October 7, 2023Data-Link-Layer
October 7, 2023Computer-Networks
| Question 37 |
A serial transmission T1 uses 8 information bits, 2 start bits, 1 stop bit and 1 parity bit for each character. A synchronous transmission T2 uses 3 eight bit sync characters followed by 30 eight bit information characters. If the bit rate is 1200 bits/second in both cases, what are the transfer rates of T1 and T2?
| 100 characters/sec, 153 characters/sec | |
| 80 characters/sec, 136 characters/sec | |
| 100 characters/sec, 136 characters/sec | |
| 80 characters/sec, 153 characters/sec |
Question 37 Explanation:
T1: 1 char = (8 + 2 + 1 + 1) = 12 bits
Transfer rate = 1200/12 = 100 char/sec
T2: Transfer character in bits = 24 + 240 = 264 bits
In 264 = 30 characters
Then in 1200 = ?
264/30 = 1200/x
x = 136.3 char/sec
So, correct option is (C).
Transfer rate = 1200/12 = 100 char/sec
T2: Transfer character in bits = 24 + 240 = 264 bits
In 264 = 30 characters
Then in 1200 = ?
264/30 = 1200/x
x = 136.3 char/sec
So, correct option is (C).
Correct Answer: C
Question 37 Explanation:
T1: 1 char = (8 + 2 + 1 + 1) = 12 bits
Transfer rate = 1200/12 = 100 char/sec
T2: Transfer character in bits = 24 + 240 = 264 bits
In 264 = 30 characters
Then in 1200 = ?
264/30 = 1200/x
x = 136.3 char/sec
So, correct option is (C).
Transfer rate = 1200/12 = 100 char/sec
T2: Transfer character in bits = 24 + 240 = 264 bits
In 264 = 30 characters
Then in 1200 = ?
264/30 = 1200/x
x = 136.3 char/sec
So, correct option is (C).
Subscribe
Login
0 Comments