Question 10004 – Operating-Systems
November 7, 2023Question 6885 – Theory-of-Computation
November 7, 2023Question 8084 – Operating-Systems
Consider a computer system with 40-bit virtual addressing and page size of sixteen kilobytes. If the computer system has a one-level page table per process and each page table entry requires 48 bits, then the size of the per-process page table is __________ megabytes.
Correct Answer: A
Question 4 Explanation:
From the above question, we got the following information.
Size of memory = 240 and Page size = 16 KB = 214
No. of pages = size of Memory / page size = 240/ 214 = 226
Size of page table = 226 * 48 / 8 bytes = 26 * 6 MB = 384 MB
Size of memory = 240 and Page size = 16 KB = 214
No. of pages = size of Memory / page size = 240/ 214 = 226
Size of page table = 226 * 48 / 8 bytes = 26 * 6 MB = 384 MB
384 MB
385 MB
386 MB
387 MB
Subscribe
Login
0 Comments