Question 14024 – NIC-NIELIT Scientist-B 2020
November 14, 2023Question 16817 – Data-Interpretation
November 14, 2023Question 14023 – NIC-NIELIT Scientist-B 2020
Directions – Question number 41 and 42 are based on the diagram given below:
In a class there are 40 students who play at least one game out of Football, Cricket and Badminton.
Q41. What percentage of students play only one game?
Correct Answer: B
Question 41 Explanation:
X(μ)= 40
X(μ)= 9+6+8+4+2+7+X(C ∩ F ∩ B)
40= 36 + X(C ∩ F ∩ B)
X(C ∩ F ∩ B) = 40=36
= 4
According to given data, Percentage of students who play only one game.
= [X(only C) + X(only F) + X(only B)] / X(μ)
= [(9 + 8 +7)/40]*100
= (24/40)*100
= 60%
50%
60%
65%
70%
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