Question 3588 – Software-requirements
November 16, 2023Question 3730 – Operating-Systems
November 16, 2023Question 3731 – Operating-Systems
Consider a disk with 16384 bytes per track having a rotation time of 16 msec and average seek time of 40 msec. What is the time in msec to read a block of 1024 bytes from this disk?
Correct Answer: B
Question 562 Explanation:
Given data,
— Bytes per track=16384
— Rotational time=16 msec.
— Average seek time= 40 msec
— What is the time in msec to read a block of 1024 bytes from this disk?
Step-1: Total time= Seek Time + Rotational Latency + Transfer Time
= ? + ? + 40 msec
Step-2: Transfer time = ((1024 bytes *16 ms)/ (16384 bytes ))
= 1 msec
Step-3: Rotational latency = 16 msec / 2
= 8 msec
Step-4: Total time= Seek Time + Rotational Latency + Transfer Time
= 40+8+1 msec
= 49 msec
— Bytes per track=16384
— Rotational time=16 msec.
— Average seek time= 40 msec
— What is the time in msec to read a block of 1024 bytes from this disk?
Step-1: Total time= Seek Time + Rotational Latency + Transfer Time
= ? + ? + 40 msec
Step-2: Transfer time = ((1024 bytes *16 ms)/ (16384 bytes ))
= 1 msec
Step-3: Rotational latency = 16 msec / 2
= 8 msec
Step-4: Total time= Seek Time + Rotational Latency + Transfer Time
= 40+8+1 msec
= 49 msec
57 sec
49 sec
48 sec
17 sec
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