GATE 2018

Question 16

Consider a long-lived TCP session with an end-to-end bandwidth of 1 Gbps (= 10⁹ bits/second). The session starts with a sequence number of 1234. The minimum time (in seconds, rounded to the closest integer) before this sequence number can be used again is _________.

A	33
B	34
C	35
D	36

Computer-NetworksTCPVideo-Explanation

Question 16 Explanation:

In TCP, Sequence number field is 32 bit, which means 2³² sequence number per byte are possible. Whatever be the starting sequence number the possible number will be 2³²bytes

The process of using all the sequence number and repeating a previously used sequence number.
The time taken to wrap around is called wrap around time:
Minimum Time = Wrap around time = Total number of bits in sequence number / Bandwidth
= 2³² * 8 / 10⁹ = 34.35 == 34 (closest integer)

Correct Answer: B

Question 16 Explanation:

In TCP, Sequence number field is 32 bit, which means 2³² sequence number per byte are possible. Whatever be the starting sequence number the possible number will be 2³²bytes

The process of using all the sequence number and repeating a previously used sequence number.
The time taken to wrap around is called wrap around time:
Minimum Time = Wrap around time = Total number of bits in sequence number / Bandwidth
= 2³² * 8 / 10⁹ = 34.35 == 34 (closest integer)

Question 7824 – Computer-Networks

Question 3676 – Data-Structures

Question 7824 – Computer-Networks

Question 3676 – Data-Structures

GATE 2018

Binu Jose A

Question 7824 – Computer-Networks

Question 3676 – Data-Structures

Question 7824 – Computer-Networks

Question 3676 – Data-Structures

Binu Jose A

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