Question 2558 – Web-Technologies
December 6, 2023UGC NET CS 2014 June-paper-3
December 6, 2023UGC NET CS 2014 June-paper-3
Question 8 |
Consider a fuzzy set old as defined below Old = {(20, 0.1), (30, 0.2), (40, 0.4), (50, 0.6), (60, 0.8), (70, 1), (80, 1)} Then the alpha-cut for alpha = 0.4 for the set old will be
{(40, 0.4)} | |
{50, 60, 70, 80} | |
{(20, 0.1), (30, 0.2)} | |
{(20, 0), (30, 0), (40, 1), (50, 1), (60, 1), (70, 1), (80, 1)} |
Question 8 Explanation:
If the membership of an element is greater than or equal to alpha-cut value then its membership will become one in the resultant set otherwise it’s membership will be zero(i.e. Will not be a member of the resulting set).
Here alpha = 0.4
So new set = {(20, 0), (30, 0), (40, 1), (50, 1), (60, 1), (70, 1), (80, 1)}
OR
{(40, 1), (50,1), (60.1), (70,1), (80,1)}
Here alpha = 0.4
So new set = {(20, 0), (30, 0), (40, 1), (50, 1), (60, 1), (70, 1), (80, 1)}
OR
{(40, 1), (50,1), (60.1), (70,1), (80,1)}
Correct Answer: D
Question 8 Explanation:
If the membership of an element is greater than or equal to alpha-cut value then its membership will become one in the resultant set otherwise it’s membership will be zero(i.e. Will not be a member of the resulting set).
Here alpha = 0.4
So new set = {(20, 0), (30, 0), (40, 1), (50, 1), (60, 1), (70, 1), (80, 1)}
OR
{(40, 1), (50,1), (60.1), (70,1), (80,1)}
Here alpha = 0.4
So new set = {(20, 0), (30, 0), (40, 1), (50, 1), (60, 1), (70, 1), (80, 1)}
OR
{(40, 1), (50,1), (60.1), (70,1), (80,1)}
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