Question 846 – Engineering-Mathematics
December 6, 2023Question 976 – Engineering-Mathematics
December 6, 2023Question 873 – Engineering-Mathematics
Consider the set of all possible five-card poker hands dealt fairly from a standard deck of fifty-two cards. How many atomic events are there in the joint probability distribution ?
Correct Answer: A
Question 653 Explanation:
→ Joint probability distribution:
Given random variables X, Y, …, that are defined on a probability space, the joint probability distribution for X, Y, … is a probability distribution that gives the probability that each of X, Y, … falls in any particular range or discrete set of values specified for that variable. In the case of only two random variables, this is called a bivariate distribution, but the concept generalizes to any number of random variables, giving a multivariate distribution.
Given data,
– Total cards = 52
– poker hand = 5 cards of all possibilities
Step-1: This problem, we are simply finding combinations of 52C5
= C(n,r) = C(52,5)
= 52! / (5!(52-5)!)
= 2598960
Given random variables X, Y, …, that are defined on a probability space, the joint probability distribution for X, Y, … is a probability distribution that gives the probability that each of X, Y, … falls in any particular range or discrete set of values specified for that variable. In the case of only two random variables, this is called a bivariate distribution, but the concept generalizes to any number of random variables, giving a multivariate distribution.
Given data,
– Total cards = 52
– poker hand = 5 cards of all possibilities
Step-1: This problem, we are simply finding combinations of 52C5
= C(n,r) = C(52,5)
= 52! / (5!(52-5)!)
= 2598960
2,598,960
3,468,960
3,958,590
2,645,590
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