GATE 2014 [Set-2]
January 17, 2024Question 13835 – Teaching Aptitude
January 17, 2024Pipelining
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Question 8
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A 4-stage pipeline has the stage delays as 150, 120, 160 and 140 nanoseconds respectively. Registers that are used between the stages have a delay of 5 nanoseconds each. Assuming constant clocking rate, the total time taken to process 1000 data items on this pipeline will be
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120.4 microseconds
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160.5 microseconds
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165.5 microseconds
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590.0 microseconds
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Question 8 Explanation:
First instruction will take complete four cycle for execution. And then after that all 999 instruction will take only 1 cycle for execution to be completed. So time required to process 1000 instruction or data items is,
1st instruction × 4 × clock time + 999 instruction × 1 × clock time
1 × 4 × 165ns + 999 × 1 × 165ns
= 1654.95ns
= 165.5μs
1st instruction × 4 × clock time + 999 instruction × 1 × clock time
1 × 4 × 165ns + 999 × 1 × 165ns
= 1654.95ns
= 165.5μs
Correct Answer: C
Question 8 Explanation:
First instruction will take complete four cycle for execution. And then after that all 999 instruction will take only 1 cycle for execution to be completed. So time required to process 1000 instruction or data items is,
1st instruction × 4 × clock time + 999 instruction × 1 × clock time
1 × 4 × 165ns + 999 × 1 × 165ns
= 1654.95ns
= 165.5μs
1st instruction × 4 × clock time + 999 instruction × 1 × clock time
1 × 4 × 165ns + 999 × 1 × 165ns
= 1654.95ns
= 165.5μs