ISRO CS-2023
January 19, 2024Normalization
January 20, 2024Operating-Systems
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Question 17
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Three processes arrive at time zero with CPU bursts of 16, 20 and 10 milliseconds. If the scheduler has prior knowledge about the length of the CPU bursts, the minimum achievable average waiting time for these three processes in a non-preemptive scheduler (rounded to nearest integer) is _________ milliseconds.
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12
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Question 17 Explanation:
Minimum average waiting time amongst non-preemptive scheduling is given by SJF.
So, avg waiting time = (0+10+26)/3 = 12 ms.
So, avg waiting time = (0+10+26)/3 = 12 ms.
Correct Answer: A
Question 17 Explanation:
Minimum average waiting time amongst non-preemptive scheduling is given by SJF.
So, avg waiting time = (0+10+26)/3 = 12 ms.
So, avg waiting time = (0+10+26)/3 = 12 ms.