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Question 9016 – GATE 2010
January 21, 2024
Question 9019 – GATE 2010
January 21, 2024
Question 9016 – GATE 2010
January 21, 2024
Question 9019 – GATE 2010
January 21, 2024

Question 9017 – GATE 2010

What is the possible number of reflexive relations on a set of 5 elements?

Correct Answer: C

Question 3 Explanation: 
Let set = ‘A’ with ‘n’ elements,

Definition of Reflexive relation:

A relation ‘R’ is reflexive if it contains xRx ∀ x∈A
A relation with all diagonal elements, it can contain any combination of non-diagonal elements.

Eg:
A={1, 2, 3}

So for a relation to be reflexive, it should contain all diagonal elements. In addition to them, we can have possible combination of (n2-n)non-diagonal elements (i.e., 2n2-n)

Ex:
{(1,1)(2,2)(3,3)} —– ‘0’ non-diagonal element
{(1,1)(2,2)(3,3)(1,2)} —– ‘1’ non-diagonal element
{(1,1)(2,2)(3,3)(1,2)(1,3)} “
___________ “
___________ “
{(1,1)(2,2)(3,3)(1,2)(1,3)(2,1)(2,3)(3,1)(3,2)} (n2-n) diagonal elements
____________________

Total: 2n2-n
For the given question n = 5.
The number of reflexive relations = 2(25-5) = 220

A
210
B
215
C
220
D
225
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