Question 9242 – GATE 2007
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<p align="Consider the schema R = (S T U V) and the dependencies S → T, T → U, U → V and V → S. Let R = (R1 and R2) be a decomposition such that R1 ∩ R2 = ∅ . The decomposition is
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not in 2NF
in 2NF but not 3NF
in 3NF but not in 2NF
in both 2NF and 3NF
Question 32 Explanation:
Since R1 ∩ R2 = ∅, so the decomposition is lossless join. Now since all the attributes are keys, so R1 ∩ R2 will be a key of the decomposed relation.
And since every attribute is key so the decomposed relation will be in BCNF and hence in 3NF. Correct Answer: D Question 32 Explanation:
Since R1 ∩ R2 = ∅, so the decomposition is lossless join. Now since all the attributes are keys, so R1 ∩ R2 will be a key of the decomposed relation.
And since every attribute is key so the decomposed relation will be in BCNF and hence in 3NF. |
not in 2NF
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in 2NF but not 3NF
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in 3NF but not in 2NF
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in both 2NF and 3NF
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