NTA UGC NET Dec 2023 Paper-2
February 8, 2024GATE 2008
February 8, 2024Computer-Networks
Question 25
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135
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1 frames takes = Tt = L / B.w. => 1000 / 10^6 = 1 millisec
1000 frame Tt = 1000 x 1 millisec = 1 sec
In 1 sec, 1000 frames sends, which is 1 millisec per frame.
So, G = 1
Efficiency of Pure Aloha (η) = G x e-2G
where G = Number of requests per time slot willing to transmit.
e = Mathematical constant approximately equal to 2.718
So, η = 1 x 2.718(-2 x 1) = 0.1353
Therefore, In 1 sec1000 frames = 0.1353 x 1000 = 135.3(closest integer) =>135
Throughput => 135
1 frames takes = Tt = L / B.w. => 1000 / 10^6 = 1 millisec
1000 frame Tt = 1000 x 1 millisec = 1 sec
In 1 sec, 1000 frames sends, which is 1 millisec per frame.
So, G = 1
Efficiency of Pure Aloha (η) = G x e-2G
where G = Number of requests per time slot willing to transmit.
e = Mathematical constant approximately equal to 2.718
So, η = 1 x 2.718(-2 x 1) = 0.1353
Therefore, In 1 sec1000 frames = 0.1353 x 1000 = 135.3(closest integer) =>135
Throughput => 135