Question 3714 – UGC NET CS 2015 Dec- paper-2
March 14, 2024Question 10830 – APPSC-2016-DL-CS
March 14, 2024APPSC-2016-DL-CS
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Question 2
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In first order predicate logic, ∼∀x P(x) is equivalent to
Options:
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∼∃x P(x)
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∃x ∼P(x)
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∀x ∼P(x)
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the given expression is not a well formed
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Question 2 Explanation:
∼∀x P(x) = ∃x ∼P(x)
Correct Answer: B
Question 2 Explanation:
∼∀x P(x) = ∃x ∼P(x)
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