UGC NET CS 2011 Dec-Paper-2
March 25, 2024Question 13058 – Operating-Systems
March 25, 2024Question 13234 – Operating-Systems
A system has a 24-bit processor and uses a page size of 2KB. Considering that
all the registers in the processor are limited to 24 bits, how many entries may be
expected in the page table?
Correct Answer: A
Question 940 Explanation:
Lets first find offset bits,
2KB = 2^11 B. So offset bits = 11
Hence no. of page table entries is = 2^(24-11) = 2^13 = 8192
2KB = 2^11 B. So offset bits = 11
Hence no. of page table entries is = 2^(24-11) = 2^13 = 8192
8192
4096
2048
None of the above.