Question 11498 – APPSC-2012-DL CA
March 27, 2024Question 11501 – APPSC-2012-DL CA
March 27, 2024Question 11499 – APPSC-2012-DL CA
What should be the access time of cache memory in order to achieve 98% hit ratio, if the memory access time in 200ns and effective access time required is 20ns?
Correct Answer: A
Question 29 Explanation:
EMAT = 0.98 × Hit time of cache + 0.02 × (200 + Hit time of cache)
20 = 0.98 × H + 0.02 (200 + H)
20 = 0.98H + 0.02 × 200 + 0.02H
20 = 0.98H + 4 + 0.02H
16 = H
∴ Access time of cache memory = 16 ns
20 = 0.98 × H + 0.02 (200 + H)
20 = 0.98H + 0.02 × 200 + 0.02H
20 = 0.98H + 4 + 0.02H
16 = H
∴ Access time of cache memory = 16 ns
16ns
18ns
20ns
10ns