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April 14, 2024Bit-Rate
April 14, 2024Question 6915 – UGC NET CS 2015 Dec – paper-3
A network with a bandwidth of 10 Mbps can pass only an average of 15,000 frames per minute with each frame carrying an average of 8,000 bits. What is the throughput of this network?
Correct Answer: A
Question 11 Explanation:
1 minute – 1500 frames
60 seconds – 1500 frames
1 second – 1500/60 frames
1 second = 25 frames
Now each frame is of 8,000 bits.
So total bits in 1 second = 25 × 80 bits
= 25×8000/1000000 Mbps
= 200/100 Mbps
= 2 Mbps
60 seconds – 1500 frames
1 second – 1500/60 frames
1 second = 25 frames
Now each frame is of 8,000 bits.
So total bits in 1 second = 25 × 80 bits
= 25×8000/1000000 Mbps
= 200/100 Mbps
= 2 Mbps
2 Mbps
60 Mbps
120 Mbps
10 Mbps