Question 3685 – Computer-Organization

Step-1: MVI A, 42H given 42 value in hexadecimal and storing value in Accumulator A.
For solving problem, convert (42)​ ₁₆​ into decimal is (66)​ ₁₀
Step-2: MVI B, 05H given 05 value in hexadecimal and storing value in Accumulator B.
For solving problem, convert (05)​ ₁₆​ into decimal is (05)​ ₁₀
Step-3: ADD B until UGC will fail. Contents of accumulator A value and B value will add.
66+5=71
Step-4: DCR B it means decrement by 1.
71+4=75
Step-5: JNZ means jump not equals to zero.
75+3=78
78+2=80
80+1=81
Step-6: It became false, then execute next statement.
ADI 25H means add 25H to (81)_{​ 10}
(25)​ ₁₆​ = (37)_{​ 10}
37+81=(118)​ ₁₀
Finally
convert decimal value into Hexadecimal.
(118)​ ₁₀​ = (76)_{​ 16}
Step-7: HLT means halt the program.
Note: We are converting hexadecimal into decimal for only calculation. without conversion also we can solve a problem.