CMI PHD 2022
August 16, 2024Computer-Networks
August 17, 2024Bandwidth
| Question 1 |
Consider the data transfer using TCP over a 1 Gbps link. Assuming that the maximum segment lifetime (MSL) is set to 60 seconds, the minimum number of bits required for the sequence number field of the TCP header, to prevent the sequence number space from wrapping around during the MSL is____________.
| 33 |
Question 1 Explanation:
Bandwidth = 1Gbps =2^30 / 8 bps
1 sec = 20^30 / 8 bytes
=> 1 sec = 20^30 / 8 sequence number
=> 60 sec =20^30 x 60 / 8 bytes
Number of sequence bits required = log (20^30 x 60 / 8) => 33
1 sec = 20^30 / 8 bytes
=> 1 sec = 20^30 / 8 sequence number
=> 60 sec =20^30 x 60 / 8 bytes
Number of sequence bits required = log (20^30 x 60 / 8) => 33
Correct Answer: A
Question 1 Explanation:
Bandwidth = 1Gbps =2^30 / 8 bps
1 sec = 20^30 / 8 bytes
=> 1 sec = 20^30 / 8 sequence number
=> 60 sec =20^30 x 60 / 8 bytes
Number of sequence bits required = log (20^30 x 60 / 8) => 33
1 sec = 20^30 / 8 bytes
=> 1 sec = 20^30 / 8 sequence number
=> 60 sec =20^30 x 60 / 8 bytes
Number of sequence bits required = log (20^30 x 60 / 8) => 33