Computer-Networks
August 29, 2024Computer-Networks
August 29, 2024Computer-Networks
| Question 317 |
Two systems S1 and S2 are configured with the following IP address:
S1: 203.197.2.53; netmask 255.255.128.0
S2: 203. 197.75.201;netmask 255.255.192.0
Which one of the following statements is true?
| S1 assumes S2 is on same network, but S2 assumes S1 is on a different network | |
| S2 assumes S1 is on same network, but S1 assumes S2 is on a different network | |
| S1 and S2 both assume they are on the same network | |
| S1 and S2 both assume they are on different networks |
Question 317 Explanation:
For S1,
IP address – 203.197.2.53
So Netmask – 255.255.128.0
For S2,
IP address – 203.197.75.201
Netmask – 255.255.192.0
Now first let’s check for S1,
Network ID according to S1 for itself,
203.197.2.53
AND 255.255.128.0
——————————-
203.197.0.0
Network ID according to S1 for S2,
203.197.75.201
255.255.128.0
———————
203.197.0.0
Since according to S1 NID of both S1 and S2 are the same, it assumes S2 to be in the same network.
Now let’s check for S2,
Network ID according to S2 for itself,
203.197.75.201
AND 255.255.192.0
——————————-
203.197.264.0
Network ID according to S2 for S1,
203.197.2.53
255.255.192.0
———————
203.197.0.0
Since according to S2 NID of both S1 and S2 are different, so it assumes S1 to be in a different network.
IP address – 203.197.2.53
So Netmask – 255.255.128.0
For S2,
IP address – 203.197.75.201
Netmask – 255.255.192.0
Now first let’s check for S1,
Network ID according to S1 for itself,
203.197.2.53
AND 255.255.128.0
——————————-
203.197.0.0
Network ID according to S1 for S2,
203.197.75.201
255.255.128.0
———————
203.197.0.0
Since according to S1 NID of both S1 and S2 are the same, it assumes S2 to be in the same network.
Now let’s check for S2,
Network ID according to S2 for itself,
203.197.75.201
AND 255.255.192.0
——————————-
203.197.264.0
Network ID according to S2 for S1,
203.197.2.53
255.255.192.0
———————
203.197.0.0
Since according to S2 NID of both S1 and S2 are different, so it assumes S1 to be in a different network.
Correct Answer: A
Question 317 Explanation:
For S1,
IP address – 203.197.2.53
So Netmask – 255.255.128.0
For S2,
IP address – 203.197.75.201
Netmask – 255.255.192.0
Now first let’s check for S1,
Network ID according to S1 for itself,
203.197.2.53
AND 255.255.128.0
——————————-
203.197.0.0
Network ID according to S1 for S2,
203.197.75.201
255.255.128.0
———————
203.197.0.0
Since according to S1 NID of both S1 and S2 are the same, it assumes S2 to be in the same network.
Now let’s check for S2,
Network ID according to S2 for itself,
203.197.75.201
AND 255.255.192.0
——————————-
203.197.264.0
Network ID according to S2 for S1,
203.197.2.53
255.255.192.0
———————
203.197.0.0
Since according to S2 NID of both S1 and S2 are different, so it assumes S1 to be in a different network.
IP address – 203.197.2.53
So Netmask – 255.255.128.0
For S2,
IP address – 203.197.75.201
Netmask – 255.255.192.0
Now first let’s check for S1,
Network ID according to S1 for itself,
203.197.2.53
AND 255.255.128.0
——————————-
203.197.0.0
Network ID according to S1 for S2,
203.197.75.201
255.255.128.0
———————
203.197.0.0
Since according to S1 NID of both S1 and S2 are the same, it assumes S2 to be in the same network.
Now let’s check for S2,
Network ID according to S2 for itself,
203.197.75.201
AND 255.255.192.0
——————————-
203.197.264.0
Network ID according to S2 for S1,
203.197.2.53
255.255.192.0
———————
203.197.0.0
Since according to S2 NID of both S1 and S2 are different, so it assumes S1 to be in a different network.
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