Computer-Networks
August 29, 2024Computer-Networks
August 29, 2024Computer-Networks
Question 392 |
Consider the classful addressing, the IP address 128.252.144.84 denotes:
0.0.0.0 as network ID and 128.252.252.84 as node ID | |
128.0.0.0 as network ID and 128.252.127.84 as node ID | |
128.252.144.0 as network ID and 128.252.144.84 as node ID
| |
128.252.0.0 as network ID and 128.252.144.84 as node ID
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Question 392 Explanation:
The range of class B IP addresses is 128-191. So first octet of given IP address is 128 ,hence the given IP address is of class B in which first two octet or first 16 bit is Network ID which remains same for all IP address of that network and rest bits are part of host ID which will be zero for Network ID of the given network.
So the Network ID of given IP address will be 128.252.0.0. And the node ID will be the same as the given IP address which is 128.252.144.84.
So the Network ID of given IP address will be 128.252.0.0. And the node ID will be the same as the given IP address which is 128.252.144.84.
Correct Answer: D
Question 392 Explanation:
The range of class B IP addresses is 128-191. So first octet of given IP address is 128 ,hence the given IP address is of class B in which first two octet or first 16 bit is Network ID which remains same for all IP address of that network and rest bits are part of host ID which will be zero for Network ID of the given network.
So the Network ID of given IP address will be 128.252.0.0. And the node ID will be the same as the given IP address which is 128.252.144.84.
So the Network ID of given IP address will be 128.252.0.0. And the node ID will be the same as the given IP address which is 128.252.144.84.
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