Computer-Networks
August 30, 2024Computer-Networks
August 30, 2024Computer-Networks
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Question 780
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The maximum data rate of a channel of 3000 Hz bandwidth and SNR of 30 db is
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60000
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15000
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30000
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3000
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Question 780 Explanation:
Maximum number of bps = B log2 (1 + SNR).
=3000*log2(1+30)
=3000*4.95
=14850. So approximately, 15000
=3000*log2(1+30)
=3000*4.95
=14850. So approximately, 15000
Correct Answer: B
Question 780 Explanation:
Maximum number of bps = B log2 (1 + SNR).
=3000*log2(1+30)
=3000*4.95
=14850. So approximately, 15000
=3000*log2(1+30)
=3000*4.95
=14850. So approximately, 15000