Computer-Networks
September 12, 2024Ethernet
September 12, 2024IP-Address
| Question 6 |
Host X has IP address 192.168.1.97 and is connected through two routers R1 and R2 to another host Y with IP address 192.168.1.80. Router R1 has IP addresses 192.168.1.135 and 192.168.1.110. R2 has IP addresses 192.168.1.67 and 192.168.1.155. The netmask used in the network is 255.255.255.224.
Given the information above, how many distinct subnets are guaranteed to already exist in the network?
| 1 | |
| 2 | |
| 3 | |
| 6 |
Question 6 Explanation:
Simply, Bitwise AND the bits of fourth octet for each of the following IP address with fourth octet of subnet mask. You will get only
XX.XX.XX.96, XX.XX.XX.64 and XX.XX.XX.128.
XX.XX.XX.96, XX.XX.XX.64 and XX.XX.XX.128.
Correct Answer: C
Question 6 Explanation:
Simply, Bitwise AND the bits of fourth octet for each of the following IP address with fourth octet of subnet mask. You will get only
XX.XX.XX.96, XX.XX.XX.64 and XX.XX.XX.128.
XX.XX.XX.96, XX.XX.XX.64 and XX.XX.XX.128.