DSSSB TGT 2017
October 11, 2024ISRO CS 2008
October 12, 2024Bit-rate
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Question 7
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Assume that we need to download text documents at the rate of 100 pages per minute. A page is an average of 24 lines with 80 characters in each line and each character requires 8 bits. Then the required bit rate of the channel is _____.
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1.636 Kbps
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1.636 Mbps
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3.272 Mbps
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3.272 Kbps
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None of the above
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Question 7 Explanation:
— Number of Pages(P)=100 per Minute
— Number of Lines(L)= 24
— Number of characters(C) =80
— One character(O) =8 bits
— Bit rate of channel=?
Step-1: Bit rate of channel= P*L*C*O
Correct Answer: E
Question 7 Explanation:
— Number of Pages(P)=100 per Minute
— Number of Lines(L)= 24
— Number of characters(C) =80
— One character(O) =8 bits
— Bit rate of channel=?
Step-1: Bit rate of channel= P*L*C*O