Question 3337 – 2015 December NTA UGC NET Paper 1
November 15, 2023Question 11129 – Engineering-Mathematics
November 15, 2023Question 7796 – Digital-Logic-Design
Which one of the following is NOT a valid identity?
Correct Answer: A
Question 4 Explanation:
Let x=1, y=1, z=0.
(x+y) ⊕ z = (1+1)⊕ 0 = 1 ⊕ 0 = 1
x ⊕ (y+z) = 1⊕(1+0) = 1 ⊕ 1 = 0
So,
(x+y) ⊕ z ≠ x ⊕ (y+z)
(x+y) ⊕ z = (1+1)⊕ 0 = 1 ⊕ 0 = 1
x ⊕ (y+z) = 1⊕(1+0) = 1 ⊕ 1 = 0
So,
(x+y) ⊕ z ≠ x ⊕ (y+z)
(x + y) ⊕ z = x ⊕ (y + z)
(x ⊕ y) ⊕ z = x ⊕ (y ⊕ z)
x ⊕ y = x + y, if xy = 0
x ⊕ y = (xy + x’y’)’
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