Question 6984 – UGC-NET June CS 2019 Paper 1
November 29, 2023Question 6986 – UGC-NET June CS 2019 Paper 1
November 29, 2023Computer-Networks
| Question 314 |
Computer P sends 64 byte messages to Computer Q through a sliding window protocol. The
delay between P and Q is 160 ms and the bandwidth is 256 kbps. What is the optimal size of
the window for P to send messages?
delay between P and Q is 160 ms and the bandwidth is 256 kbps. What is the optimal size of
the window for P to send messages?
| 40 | |
| 80 | |
| 320 | |
| 640 | |
| None of the above
|
Question 314 Explanation:
Optimal window size = 2a
where a = Tp/Tt
Tp is given as 160ms
Tt = L/B = 64×8/256×103 = 29/28 ms = 2 ms
∴ Optimal window size = 2 × Tp/Tt = 2 × 160/2 = 160
where a = Tp/Tt
Tp is given as 160ms
Tt = L/B = 64×8/256×103 = 29/28 ms = 2 ms
∴ Optimal window size = 2 × Tp/Tt = 2 × 160/2 = 160
Correct Answer: E
Question 314 Explanation:
Optimal window size = 2a
where a = Tp/Tt
Tp is given as 160ms
Tt = L/B = 64×8/256×103 = 29/28 ms = 2 ms
∴ Optimal window size = 2 × Tp/Tt = 2 × 160/2 = 160
where a = Tp/Tt
Tp is given as 160ms
Tt = L/B = 64×8/256×103 = 29/28 ms = 2 ms
∴ Optimal window size = 2 × Tp/Tt = 2 × 160/2 = 160