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Question 4072 – UGC NET CS 2005 Dec-Paper-2
January 16, 2024Question 8610 – Aptitude
January 17, 2024GATE 2014 [Set-2]
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Question 4
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What is the average of all multiples of 10 from 2 to 198?
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90
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100
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110
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120
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Question 4 Explanation:
Average of 10, 20, 30, …, 180, 190
Average = 10+20+30+…+180+190 / 19 = (19/2 [10+190]) / 19 = 100
Average = 10+20+30+…+180+190 / 19 = (19/2 [10+190]) / 19 = 100
Correct Answer: B
Question 4 Explanation:
Average of 10, 20, 30, …, 180, 190
Average = 10+20+30+…+180+190 / 19 = (19/2 [10+190]) / 19 = 100
Average = 10+20+30+…+180+190 / 19 = (19/2 [10+190]) / 19 = 100