Question 6032 – UGC NET CS 2008 Dec-Paper-2
January 20, 2024Question 3971 – 2006 December UGC NET Paper 1
January 20, 2024Question 6033 – UGC NET CS 2008 Dec-Paper-2
A relation R in {1, 2, 3, 4, 5, 6} is given by { (1, 2), (2, 3), (3, 4), (4, 4), (4, 5) }. This relation is :
Correct Answer: D
Question 12 Explanation:
Reflexive: A relation R is said to be reflexive if for all elements of a set x belongs to R (x,x) exists.
Since in above question {(1,1), (2,2),(3,3),(4,4),(5,5),(6,6)} does not exist in given relation so it is not reflexive.
Symmetric: A relation R is symmetric if (x,y) belong to R then (y,x) must belong to R.
Since in above question (1,2) exists but (2,1) does not exist in given relation so given relation is not symmetric.
Transitive: A relation is transitive if (x,y) belongs to R and (y,z) belongs to R then (x,z) must belongs to R.
In above question (1, 2), (2, 3) exist in given relation but (1,3) does not exist there so given relation is not transitive.
Hence correct option is option(D)
Since in above question {(1,1), (2,2),(3,3),(4,4),(5,5),(6,6)} does not exist in given relation so it is not reflexive.
Symmetric: A relation R is symmetric if (x,y) belong to R then (y,x) must belong to R.
Since in above question (1,2) exists but (2,1) does not exist in given relation so given relation is not symmetric.
Transitive: A relation is transitive if (x,y) belongs to R and (y,z) belongs to R then (x,z) must belongs to R.
In above question (1, 2), (2, 3) exist in given relation but (1,3) does not exist there so given relation is not transitive.
Hence correct option is option(D)
reflexive
symmetric
transitive
not reflexive, not symmetric and not transitive
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