DSSSB TGT 2021
February 12, 2024Computer-Networks
February 12, 2024GATE 2007-IT
|
Question 14
|
Consider a TCP connection in a state where there are no outstanding ACKs. The sender sends two segments back to back. The sequence numbers of the first and second segments are 230 and 290 respectively. The first segment was lost, but the second segment was received correctly by the receiver. Let X be the amount of data carried in the first segment (in bytes), and Y be the ACK number sent by the receiver. The values of X and Y (in that order) are
|
60 and 290
|
|
|
230 and 291
|
|
|
60 and 231
|
|
|
60 and 230
|
Question 14 Explanation:
In the 1st segment data is from byte number 230 to byte number 289, that is 60 bytes. As 1st segment is lost, so TCP will send ACK for the next-in-order segment receiver is to be expecting. So, it will be for 230.
Correct Answer: D
Question 14 Explanation:
In the 1st segment data is from byte number 230 to byte number 289, that is 60 bytes. As 1st segment is lost, so TCP will send ACK for the next-in-order segment receiver is to be expecting. So, it will be for 230.
Subscribe
Login
0 Comments