Artificial-Intelligence
March 14, 2024APPSC-2016-DL-CS
March 14, 2024Question 3714 – UGC NET CS 2015 Dec- paper-2
Consider the following program :
#include
main( )
{
int i, inp;
float x, term=1, sum=0;
scanf(“%d %f ”, &inp, &x);
for(i=1; i<=inp; i++)
{
term = term * x/i;
sum = sum + term ;
}
printf(“Result = %f\n”, sum);
}
The program computes the sum of which of the following series?
Correct Answer: B
Question 11 Explanation:
In this problem, we have to find series of evaluation.
Let x=5, inp=5
Iteration-1:
for(i=1; i<=inp; i++)
/* condition true 1<=5 */
{
term = term * x/i;
/* (1*5)/1=5. Here, 5 nothing but ‘x’ */
sum = sum + term ; /* 0+5=5 */
}
Iteration-2: Here, ‘i’ becomes 2.
for(i=2; i<=inp; i++)
/* condition true 2<=5 */
{
term = term * x/i;
/* (5*5)/2 is nothing but x 2 /i */
sum = sum + term ; /* 5+12=17 */
}
;;;
;;;
Iteration-5: Here, ‘i’ becomes 5.
for(i=5; i<=inp; i++)
/* condition true 5<=5 */
{
term = term * x/i;
/* (625*5)/5! is nothing but x 5 /i! */
sum = sum + term ;
}
So, Option-B is correct answer.
Let x=5, inp=5
Iteration-1:
for(i=1; i<=inp; i++)
/* condition true 1<=5 */
{
term = term * x/i;
/* (1*5)/1=5. Here, 5 nothing but ‘x’ */
sum = sum + term ; /* 0+5=5 */
}
Iteration-2: Here, ‘i’ becomes 2.
for(i=2; i<=inp; i++)
/* condition true 2<=5 */
{
term = term * x/i;
/* (5*5)/2 is nothing but x 2 /i */
sum = sum + term ; /* 5+12=17 */
}
;;;
;;;
Iteration-5: Here, ‘i’ becomes 5.
for(i=5; i<=inp; i++)
/* condition true 5<=5 */
{
term = term * x/i;
/* (625*5)/5! is nothing but x 5 /i! */
sum = sum + term ;
}
So, Option-B is correct answer.
x + x 2 /2 + x 3 /3 + x 4 /4 +…
x + x 2 /2! + x 3 /3! + x 4 /4! +…
1 + x 2 /2 + x 3 /3 + x 4 /4 +…
1 + x 2 /2! + x 3 /3! + x 4 /4! +…