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March 27, 2024Question 11518 – APPSC-2012-DL CA
March 27, 2024Question 11517 – APPSC-2012-DL CA
The age of a father is twice that of the elder son. After ten years the age of the father will be three times that of younger son. If the difference of ages of the two sons is 15 years then what will be the age of the father?
Correct Answer: A
Question 47 Explanation:
Let the age of elder son = E
The age of father = 2E
Let the age of younger son = Y
Then according to question,
2E + 1 = 3(Y + 10) — (I)
and
E – Y = 15
Y = E – 15 —(II)
Putting (II) in (I),
2E + 10 = 3(E – 15 + 10)
2E + 10 = 3(E – 5)
2E + 10 = 3E – 15
25 = E
∴ Age of father = 2E = 2 × 25 = 50
The age of father = 2E
Let the age of younger son = Y
Then according to question,
2E + 1 = 3(Y + 10) — (I)
and
E – Y = 15
Y = E – 15 —(II)
Putting (II) in (I),
2E + 10 = 3(E – 15 + 10)
2E + 10 = 3(E – 5)
2E + 10 = 3E – 15
25 = E
∴ Age of father = 2E = 2 × 25 = 50
50
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