Question 3177 – Data-Interpretation
April 8, 2024UGC NET CS 2011 June-Paper-2
April 8, 2024Question 5465 – Engineering-Mathematics
What is the probability of choosing correctly an unknown integer between 0 and 9 with 3 chances ?
Correct Answer: E
Question 907 Explanation:
Probability of getting a number = 1/10
Probability of not getting a number = 1- 1/(10) = 9/10
Now probability that correct number is chosen in first chance= 1/10
probability that correct number is chosen in second chance= (9/10)* (1/10)
probability that correct number is chosen in first chance= (9/10)* (9/10) *(1/10)
So total probability = (1/10)+ [(9/10)* (1/10) ]+ [(9/10)* (9/10) *(1/10)]
= (1/10)+(9/100)+(81/1000)
= 271/1000
Note: Excluded for evaluation because given options are wrong
Probability of not getting a number = 1- 1/(10) = 9/10
Now probability that correct number is chosen in first chance= 1/10
probability that correct number is chosen in second chance= (9/10)* (1/10)
probability that correct number is chosen in first chance= (9/10)* (9/10) *(1/10)
So total probability = (1/10)+ [(9/10)* (1/10) ]+ [(9/10)* (9/10) *(1/10)]
= (1/10)+(9/100)+(81/1000)
= 271/1000
Note: Excluded for evaluation because given options are wrong
963/1000
973/1000
983/1000
953/1000
None of the above
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