NTA UGC NET Dec 2023 Paper-2
April 16, 2024Closure-Property
April 16, 2024Question 2499 – UGC NET CS 2017 Nov- paper-2
The Octal equivalent of the binary number 1011101011 is :
Correct Answer: B
Question 4 Explanation:
We have to divide binary number into 3 bit pairs from LSB.
1 011 101 011
1 3 5 3
(1011101011) 2 = (1353) 8
1 011 101 011
1 3 5 3
(1011101011) 2 = (1353) 8
7353
1353
5651
5657