NTA UGC NET Dec 2023 Paper-1
April 16, 2024Question 188 – ISRO CS 2008
April 16, 2024Computer-Networks
| Question 948 |
If the bandwidth of a signal is 5 kHz and the lowest frequency is 52 kHz, what is the highest frequency
| 5 kHz | |
| 10 kHz | |
| 47 kHz | |
| 57 kHz |
Question 948 Explanation:
Bandwidth = Highest frequency – Lowest frequency.
Highest frequency = Bandwidth+ Lowest Frequency= 5kHz + 52kHz = 57kHz.
Highest frequency = Bandwidth+ Lowest Frequency= 5kHz + 52kHz = 57kHz.
Correct Answer: D
Question 948 Explanation:
Bandwidth = Highest frequency – Lowest frequency.
Highest frequency = Bandwidth+ Lowest Frequency= 5kHz + 52kHz = 57kHz.
Highest frequency = Bandwidth+ Lowest Frequency= 5kHz + 52kHz = 57kHz.