Question 4342 – IP-Adress
May 23, 2024Question 4294 – IP-Adress
May 23, 2024UGC NET CS 2006 Dec-paper-2
| Question 29 |
The subnet mask 255.255.255.192
| Extends the network portion to 16 bits | |
| Extends the network portion to 26 bits | |
| Extends the network portion to 36 bits | |
| Has no effect on the network portion of an IP address |
Question 29 Explanation:
Default subnet mask for Class-C is 255.255.255.192
(192) 10 = (11000000) 2
Since, 192 is written as 11000000, it has 2 sub-nets and remaining all hosts.
So, for first three octets, 24 bits are fixed and for last octet 2 bits are fixed, i.e. 24 + 2 = 26 bits
(192) 10 = (11000000) 2
Since, 192 is written as 11000000, it has 2 sub-nets and remaining all hosts.
So, for first three octets, 24 bits are fixed and for last octet 2 bits are fixed, i.e. 24 + 2 = 26 bits
Correct Answer: B
Question 29 Explanation:
Default subnet mask for Class-C is 255.255.255.192
(192) 10 = (11000000) 2
Since, 192 is written as 11000000, it has 2 sub-nets and remaining all hosts.
So, for first three octets, 24 bits are fixed and for last octet 2 bits are fixed, i.e. 24 + 2 = 26 bits
(192) 10 = (11000000) 2
Since, 192 is written as 11000000, it has 2 sub-nets and remaining all hosts.
So, for first three octets, 24 bits are fixed and for last octet 2 bits are fixed, i.e. 24 + 2 = 26 bits