Question 7049 – Computer-Organization
May 30, 2024Question 15139 – DSSSB TGT 2021
May 30, 2024UGC NET June-2019 CS Paper-2
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Question 94
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Suppose that a computer program takes 100 seconds of execution time on a computer with multiplication operation responsible for 80 seconds of this time. How much do you have to improve the speed of multiplication operation if you are asked to execute this program four times faster.
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14 times faster
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15 times faster
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16 times faster
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17 times faster
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Question 94 Explanation:
Total execution time of a program = time to execute multiplication operation + time to perform some other operations
100 = 80 +time to perform some other operations
time to perform some other operations = 20
Now they are saying that improve the speed of multiplication operation if you are asked to execute this program four times faster i.e.
New Total execution time of a program = 100/4
= 25
And according to question we have to keep the time to perform some other operations as it is i.e.20.
Hence time to perform multiplication operation after modification =
(New Total execution time of a program – time to perform some other operations)
= 25-20
= 5
So the speed of multiplication operation is improved by 80/5 time
= 16 times.
100 = 80 +time to perform some other operations
time to perform some other operations = 20
Now they are saying that improve the speed of multiplication operation if you are asked to execute this program four times faster i.e.
New Total execution time of a program = 100/4
= 25
And according to question we have to keep the time to perform some other operations as it is i.e.20.
Hence time to perform multiplication operation after modification =
(New Total execution time of a program – time to perform some other operations)
= 25-20
= 5
So the speed of multiplication operation is improved by 80/5 time
= 16 times.
Correct Answer: C
Question 94 Explanation:
Total execution time of a program = time to execute multiplication operation + time to perform some other operations
100 = 80 +time to perform some other operations
time to perform some other operations = 20
Now they are saying that improve the speed of multiplication operation if you are asked to execute this program four times faster i.e.
New Total execution time of a program = 100/4
= 25
And according to question we have to keep the time to perform some other operations as it is i.e.20.
Hence time to perform multiplication operation after modification =
(New Total execution time of a program – time to perform some other operations)
= 25-20
= 5
So the speed of multiplication operation is improved by 80/5 time
= 16 times.
100 = 80 +time to perform some other operations
time to perform some other operations = 20
Now they are saying that improve the speed of multiplication operation if you are asked to execute this program four times faster i.e.
New Total execution time of a program = 100/4
= 25
And according to question we have to keep the time to perform some other operations as it is i.e.20.
Hence time to perform multiplication operation after modification =
(New Total execution time of a program – time to perform some other operations)
= 25-20
= 5
So the speed of multiplication operation is improved by 80/5 time
= 16 times.
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