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DSSSB TGT 2017
October 11, 2024
ISRO CS 2008
October 12, 2024
DSSSB TGT 2017
October 11, 2024
ISRO CS 2008
October 12, 2024

Bit-rate

Question 7
Assume that we need to download text documents at the rate of 100 pages per minute. A page is an average of 24 lines with 80 characters in each line and each character requires 8 bits. Then the required bit rate of the channel is _____.
A
1.636 Kbps
B
1.636 Mbps
C
3.272 Mbps
D
3.272 Kbps
E
None of the above
Question 7 Explanation: 
— Number of Pages(P)=100 per Minute

— Number of Lines(L)= 24

— Number of characters(C) =80

— One character(O) =8 bits

— Bit rate of channel=?

Step-1: Bit rate of channel= P*L*C*O

Correct Answer: E
Question 7 Explanation: 
— Number of Pages(P)=100 per Minute

— Number of Lines(L)= 24

— Number of characters(C) =80

— One character(O) =8 bits

— Bit rate of channel=?

Step-1: Bit rate of channel= P*L*C*O

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