Computer-Graphics
Question 1 |
A | (a)-(i), (b)-(ii), (c)-(iii), (d)-(iv), (e)-(v) |
B | (a)-(ii), (b)-(iii), (c)-(i), (d)-(iv), (e)-(v) |
C | (a)-(iii), (b)-(i), (c)-(ii), (d)-(v), (e)-(iv) |
D | (a)-(iv), (b)-(v), (c)-(i), (d)-(ii), (e)-(iii) |
Question 1 Explanation:
Flood Gun: An electron gun designed to flood the entire screen with
electrons.
Collector: Partly energized by flooding gun stores the charge generated by the writing gun.
Ground: Used to discharge the collector.
Collector: Partly energized by flooding gun stores the charge generated by the writing gun.
Ground: Used to discharge the collector.
Question 2 |
Give the number of principal vanishing point(s) along with their direction for the standard perspective transformation:
A | Only one in the direction K |
B | Two in the directions I and J |
C | Three in the directions I, J and K |
D | Only two in the directions J and K |
Question 2 Explanation:
There is only one principal vanishing point and it is in K-direction.
Question 3 |
A 4*4 DFT matrix is given by :
Where values of x and y are _____, _____ respectively.
Where values of x and y are _____, _____ respectively.
A | 1, −1 |
B | −1, 1 |
C | −j, j |
D | j, −j |
Question 4 |
Which of the following is not true in case of Oblique Projections?
A | Parallel projection rays are not perpendicular to the viewing plane. |
B | Parallel lines in space appear parallel on the final projected image. |
C | Used exclusively for pictorial purposes rather than formal working drawings. |
D | Projectors are always perpendicular to the plane of projection. |
Question 5 |
With respect to CRT, the horizontal retrace is defined as:
A | The path an electron beam takes when returning to the left side of the CRT. |
B | The path an electron beam takes when returning to the right side of the CRT. |
C | The technique of turning the electron beam off while retracing. |
D | The technique of turning the electron beam on/off while retracing. |
Question 6 |
Which of the following is not a component of Memory tube display ?
A | Flooding gun |
B | Collector |
C | Ground |
D | Liquid Crystal |
Question 6 Explanation:
Memory tube display components:
1. Connector Pins
2. Electron Gun
3. Base
4. Focusing System
5. Control Grid Voltage
6. X/Y Deflect
7. Phosphor
8. Collector
9. Ground
Note: Liquid crystal is not a component of memory tube display
.
1. Connector Pins
2. Electron Gun
3. Base
4. Focusing System
5. Control Grid Voltage
6. X/Y Deflect
7. Phosphor
8. Collector
9. Ground
Note: Liquid crystal is not a component of memory tube display
.
Question 7 |
Consider the following statement with respect to approaches to fill area on raster systems:
(P) To determine the overlap intervals for scan lines that cross the area.
(Q) To start from a given interior position and paint outward from this point until we encounter the specified boundary conditions.
Select the correct answer from the options given below:
(P) To determine the overlap intervals for scan lines that cross the area.
(Q) To start from a given interior position and paint outward from this point until we encounter the specified boundary conditions.
Select the correct answer from the options given below:
A | P only |
B | Q only |
C | Both P and Q |
D | Neither P nor Q |
Question 7 Explanation:
Fill area on raster systems:
TRUE: To determine the overlap intervals for scan lines that cross the area.
TRUE: To start from a given interior position and paint outward from this point until we encounter the specified boundary conditions.
TRUE: To determine the overlap intervals for scan lines that cross the area.
TRUE: To start from a given interior position and paint outward from this point until we encounter the specified boundary conditions.
Question 8 |
If we want to resize a 1024 × 768 pixels image to one that is 640 pixels wide with the same aspect ratio, what would be the height of the resized image?
A | 420 Pixels |
B | 460 Pixels |
C | 480 Pixels |
D | 540 Pixels |
Question 8 Explanation:
Aspect Ratio= Width / Height
Aspect ration of 1024 × 768 pixels image = 1024/768
= 4/3
Aspect ration of modified pixels image = 640/height
4/3 = 640/height
Height = (3*640)/4
Height = 480 Pixels
Aspect ration of 1024 × 768 pixels image = 1024/768
= 4/3
Aspect ration of modified pixels image = 640/height
4/3 = 640/height
Height = (3*640)/4
Height = 480 Pixels
Question 9 |
Which of the following transforms in 2 dimension is used to resize a 2-dimensional object?
A | Translation
|
B | Rotation
|
C | Scaling
|
D | Shearing |
Question 10 |
The clipping process in computer graphics is used for
A | Adding graphics
|
B | copying
|
C | Zooming
|
D | removing objects and lines |
Question 10 Explanation:
The clipping process in computer graphics is used for removing objects and lines.
Clipping is a technique used to determine which portions of an object or line are visible and should be displayed within the boundaries of a given region or window.
Any part of an object or line that falls outside this region is "clipped" or removed, ensuring that only the visible portions are rendered on the screen.
This is a fundamental operation in computer graphics used to control what is displayed within a defined viewing area or viewport.
Question 11 |
Consider the rectangle with vertices (0,0),(0,2),(3,0),(3,2).There is a scaling of 2 towards the x-axis and 3 towards the y-axis. The new coordinates of the rectangle are
A | (0,0)(6,0)(0,4)(6,4)
|
B | (0,0)(6,0)(0,4)(3,2)
|
C | (0,0)(6,0)(0,6)(6,6)
|
D | (0,0)(4,0)(0,6)(4,6) |
Question 11 Explanation:
To scale a rectangle by a factor of 2 along the x-axis and 3 along the y-axis, you can apply the scaling factor to each vertex individually. The scaling operation multiplies the x-coordinate by 2 and the y-coordinate by 3 for each vertex.
Given the original vertices of the rectangle:
(0, 0)
(0, 2)
(3, 0)
(3, 2)
After scaling, the new coordinates are:
(0 * 2, 0 * 3) = (0, 0)
(0 * 2, 2 * 3) = (0, 6)
(3 * 2, 0 * 3) = (6, 0)
(3 * 2, 2 * 3) = (6, 6)
So, the correct new coordinates of the rectangle after scaling are:
(0, 0) (0, 6) (6, 0) (6, 6)
The option that matches these coordinates is:
(0, 0) (0, 6) (6, 0) (6, 6)
Question 12 |
This transformation is called
A | Scaling |
B | Shear |
C | Homography |
D | Steganography |
Question 13 |
n the context of 3D Computer graphics, which of the following statements is/are correct?
A) Under perspective projection, each set of parallel lines in the object do not stay parallel in the image (except those that are parallel to the view plane to start with).
B) Applying a perspective transformation in the graphics pipeline to a vertex involves dividing by its ‘z’ coordinate.
C) Perspective transformation is a linear transformation.
Choose the correct answer from the options given below:
A | (A) and (B) only |
B | (A) and (C) only |
C | (B) and (C) only |
D | (A), (B) and (C) |
Question 14 |
Concerning phong shading and gouraud shading in a 3D scene, which of the following statements are true?
(A) Gouraud shading requires more computation than phong shading
(B) Gouraud shading linearly interpolates the color of an interior pixel from the color at the vertices.
(C) Phong shading interpolates over the normal vectors specified at the vertices.
Choose the correct answer from the options given below:
A | (A) and (B) only |
B | (A) and (C) only |
C | (B) and (C) only |
D | (A), (B) and (C) |
Question 15 |
Given below are two statements:
Statement I: Bezier curves are curves that interpolate all of their control points
Statement II: A cubic bezier curve has four control points.
In the light of the above statements, choose the correct answer from the options given below
A | Both statement I and Statement II are true |
B | Both Statement I and Statement II are false |
C | Statement I is correct but Statement II is false |
D | Statement I is incorrect but Statement II is true |
Question 16 |
Match List-I with List-II. List-I gives 33 matrices representing 2D transformations and List-II shows the corresponding transformation diagrams.
Choose the correct answer from the options given below:
Choose the correct answer from the options given below:
A | A-IV, B-II, C-III, D-I |
B | A-IV, B-III, C-II, D-I
|
C | A-III, B-II, C-IV, D-I |
D | A-II, B-IV, C-III, D-I |
Question 17 |
Given below are different properties of 3D projections from A.D. Identify the correct order on the basis of property true of
(i) a perspective projection only
(ii) an orthographic projection only
(iii) both orthographic and projective transformations and
(iv) neither orthographic nor projective transformation, respectively.
(A) Straight lines are mapped to straight lines.
(B) Distance and angles are (in general) preserved.
(C) Far away objects appear the same size as closer ones.
(D) Requires homogeneous coordinates in order for it to be encoded into linear transformation.
Choose the correct answer from the options given below:
A | D, C, B, A |
B | B, C, D, A
|
C | D, C, A, B |
D | C, D, B, A |
Question 18 |
Consider the following statements:
a) 3D Studio Max includes a number of high-level professional tools for character animation, game development, and visual effect production.
b) MAYA is a complete modeling package developed by Microsoft
c) RenderMan is a rendering package developed by Pixar
Which of the above statements are true?
a) 3D Studio Max includes a number of high-level professional tools for character animation, game development, and visual effect production.
b) MAYA is a complete modeling package developed by Microsoft
c) RenderMan is a rendering package developed by Pixar
Which of the above statements are true?
A | Only a and b |
B | Only a and c |
C | Only b and c |
D | a,b and c |
Question 18 Explanation:
MAYA 3D animation software offers a comprehensive creative feature set for 3D computer animation, modeling, simulation, rendering, and compositing on a highly extensible production platform. Maya has next-generation display technology, accelerated modeling workflows, and tools for handling complex data.
Question 19 |
The ____ file format allows storing an animation sequence
A | PNG |
B | GIF |
C | JPG |
D | PDF |
Question 19 Explanation:
→PDF means portable document format.
→Portable Network Graphics is a raster-graphics file-format that supports lossless data compression.
→JPG/JPEG: Joint Photographic Experts Group. JPEG is usually known as JPG. It stands for Joint Photographic Expert Group, a joint working group of International Standardization Organization (ISO) and International Electrotechnical Commission (IEC). It is a standard method of compressing graphic images.
→A GIF is a computer file that is used on the internet for sending images, especially moving images. GIF is an abbreviation for 'Graphic Interchange Format'.
→Portable Network Graphics is a raster-graphics file-format that supports lossless data compression.
→JPG/JPEG: Joint Photographic Experts Group. JPEG is usually known as JPG. It stands for Joint Photographic Expert Group, a joint working group of International Standardization Organization (ISO) and International Electrotechnical Commission (IEC). It is a standard method of compressing graphic images.
→A GIF is a computer file that is used on the internet for sending images, especially moving images. GIF is an abbreviation for 'Graphic Interchange Format'.
Question 20 |
The process of rotating the image by 1800 without changing its size is called:
A | Translation |
B | Rotation |
C | Scaling |
D | Reflection |
Question 20 Explanation:
The process of rotating the image by 1800 without changing its size is called Rotation
Question 21 |
Using Mid Point algorithm, the new coordinates of the point P(x,y) having slope ‘m’ and constant and ‘b’ is calculated using:
A | F(x,y)=mx+b-y |
B | F(x,y)=mx-y+b |
C | F(x,y)=mx+b |
D | F(x,y)=mx-y+b-y |
Question 21 Explanation:
In order to check this, we need to consider the implicit equation:
F(x,y) = mx + b - y
For positive m at any given X,
If y is on the line, then F(x, y) = 0
If y is above the line, then F(x, y) < 0
If y is below the line, then F(x, y) > 0
F(x,y) = mx + b - y
For positive m at any given X,
If y is on the line, then F(x, y) = 0
If y is above the line, then F(x, y) < 0
If y is below the line, then F(x, y) > 0
Question 22 |
Transformation that moves objects without deformation is called:
A | Rotation |
B | Scaling |
C | Translation |
D | Morphism |
Question 22 Explanation:
→ A translation process moves every point a constant distance in a specified direction. It can be described as a rigid motion.
→ A translation can also be interpreted as the addition of a constant vector to every point, or as shifting the origin of the coordinate system.
→ A translation can also be interpreted as the addition of a constant vector to every point, or as shifting the origin of the coordinate system.
Question 23 |
In 3D Graphics, which of the following statement/s is/are true ?
-
P: Back-face culling is an example of an image-precision visible-surface determination.
Q: Z-Buffer is a 16-bit, 32-bit, or 64-bit field associated with each pixel in a frame buffer
that can be used to determine the visible surface at each pixel.
Choose the correct answer from the code given below :;
Code :A | P only |
B | Q only
|
C | Neither P nor Q
|
D | P and Q
|
Question 23 Explanation:
Back Face Culling:
→ Back-face culling (an object space algorithm) works on 'solid' objects which you are looking at from the outside. That is, the polygons of the surface of the object completely enclose the object.
→ Back-face culling is not an example of an image-precision visible-surface determination.
→ Back-face culling can very quickly remove unnecessary polygons. Unfortunately there are often times when back-face culling can not be used. For example if you wish to make an open-topped box - the inside and the outside of the box both need to be visible, so either two sets of polygons must be generated, one set facing out and another facing in, or back-face culling must be turned off to draw that object.
1. Back faces: faces of opaque object which are “pointing away” from viewer.
2. Back face culling – remove back faces (supported by OpenGL).
→ TRUE: Z-Buffer is a 16-bit, 32-bit, or 64-bit field associated with each pixel in a frame buffer that can be used to determine the visible surface at each pixel.
→ Back-face culling (an object space algorithm) works on 'solid' objects which you are looking at from the outside. That is, the polygons of the surface of the object completely enclose the object.
→ Back-face culling is not an example of an image-precision visible-surface determination.
→ Back-face culling can very quickly remove unnecessary polygons. Unfortunately there are often times when back-face culling can not be used. For example if you wish to make an open-topped box - the inside and the outside of the box both need to be visible, so either two sets of polygons must be generated, one set facing out and another facing in, or back-face culling must be turned off to draw that object.
1. Back faces: faces of opaque object which are “pointing away” from viewer.
2. Back face culling – remove back faces (supported by OpenGL).
→ TRUE: Z-Buffer is a 16-bit, 32-bit, or 64-bit field associated with each pixel in a frame buffer that can be used to determine the visible surface at each pixel.
Question 24 |
In 3D Graphics, which of the following statements about perspective and parallel projection is/are true?
-
P: In a perspective projection, the farthest an object is from the center of projection, the smaller it appears.
Q: Parallel projection is equivalent to a perspective projection where the viewer is standing infinitely far away
R: Perspective projections do not preserve straight lines.
Choose the correct answer from the code given below:
Code:A | P and R only |
B | P, Q and R |
C | Q and R only |
D | P and Q only
|
Question 24 Explanation:
Perspective Projection :
Perspective projection is representing or drawing objects which resemble the real thing.
Perspective projection preserves the straight line.
In perspective projection, objects that are far away appear smaller, and objects that are near appear bigger.
Parallel lines do not remain parallel.
Distance and angles are not preserved.
Parallel Projection :
In this projection drawing objects looks less realistic.
In this projection parallel lines remains parallel.
Angles are not preserved in this projection.
It is good for exact measurements.
Perspective projection is representing or drawing objects which resemble the real thing.
Perspective projection preserves the straight line.
In perspective projection, objects that are far away appear smaller, and objects that are near appear bigger.
Parallel lines do not remain parallel.
Distance and angles are not preserved.
Parallel Projection :
In this projection drawing objects looks less realistic.
In this projection parallel lines remains parallel.
Angles are not preserved in this projection.
It is good for exact measurements.
Question 25 |
Memory mapped displays
A | are utilized for high resolution graphics such as maps |
B | uses ordinary memory to store the display data in character form |
C | stores the display data as individual bits |
D | are associated with electromechanical teleprinters |
Question 25 Explanation:
● Graphs can be displayed on a screen by writing character values into a special area of RAM within the video controller.
● Prior to cheap RAM that enabled bit-mapped displays, this character cell method was a popular technique for computer video displays.
Question 26 |
Which of the following statements is/are True regarding the solution to the visibility problem in 3D graphics ?
S1 : The Painter’s algorithm sorts polygons by depth and then paints (scan - converts) each Polygon onto the screen starting with the most nearest polygon. S2 : Backface Culling refers to eliminating geometry with back facing normals. Code :A | S1 only |
B | S2 only
|
C | Both S1 and S2 |
D | Neither S1 Nor S2 |
Question 26 Explanation:
Visibility problem in 3D graphics
1. Painter's algorithm
- A depth sorting method
- Surfaces are sorted in the order of decreasing depth
- Surfaces are drawn in the sorted order, and overwrite the pixels in the frame buffer - Subtle difference from depth buffer approach: entire face drawn
- Two problems:
• It can be nontrivial to sort the surfaces
• There can be no solution for the sorting order
2. Back Face Culling
- Back faces: faces of opaque object which are “pointing away” from viewer
- Back face culling – remove back faces (supported by OpenGL)
How to detect back faces
- If we find backface, do not draw, save rendering resources
- There must be other forward face(s) closer to eye
- F is face of object we want to test if backface
- P is a point on F
- Form view vector, V as (eye – P)
- N is normal to face F
3. View-Frustum Culling
- Remove objects that are outside the viewing frustum
- Done by 3D clipping algorithm (e.g. Liang-Barsky)
4. Ray Tracing
- Ray tracing is another example of image space method
- Ray tracing: Cast a ray from eye through each pixel to the world
5. Z(Depth buffer algorithm)
Reference: https://web.cs.wpi.edu/~emmanuel/courses/cs543/slides/lecture08_p2.pdf
1. Painter's algorithm
- A depth sorting method
- Surfaces are sorted in the order of decreasing depth
- Surfaces are drawn in the sorted order, and overwrite the pixels in the frame buffer - Subtle difference from depth buffer approach: entire face drawn
- Two problems:
• It can be nontrivial to sort the surfaces
• There can be no solution for the sorting order
2. Back Face Culling
- Back faces: faces of opaque object which are “pointing away” from viewer
- Back face culling – remove back faces (supported by OpenGL)
How to detect back faces
- If we find backface, do not draw, save rendering resources
- There must be other forward face(s) closer to eye
- F is face of object we want to test if backface
- P is a point on F
- Form view vector, V as (eye – P)
- N is normal to face F
3. View-Frustum Culling
- Remove objects that are outside the viewing frustum
- Done by 3D clipping algorithm (e.g. Liang-Barsky)
4. Ray Tracing
- Ray tracing is another example of image space method
- Ray tracing: Cast a ray from eye through each pixel to the world
5. Z(Depth buffer algorithm)
Reference: https://web.cs.wpi.edu/~emmanuel/courses/cs543/slides/lecture08_p2.pdf
Question 27 |
A frame buffer array is addressed in row major order for a monitor with pixel locations starting from (0,0) and ending with (100,100). What is address of the pixel(6,10)? Assume one bit storage per pixel and starting pixel location is at 0.
A | 1016 |
B | 1006 |
C | 610 |
D | 616 |
Question 27 Explanation:
Given data,
Pixel location starts from =(0,0)
Pixel location ends from =(100,100)
Address of the pixel= ?
Hint: Frame buffer array is addressed in row major order
. Step-1: Row major order is= 0+1((6-0)+101(10-0))
= 0+6+1010
= 1016
Pixel location starts from =(0,0)
Pixel location ends from =(100,100)
Address of the pixel= ?
Hint: Frame buffer array is addressed in row major order
. Step-1: Row major order is= 0+1((6-0)+101(10-0))
= 0+6+1010
= 1016
Question 28 |
How much memory is required to implement the z-buffer algorithm for a 512 x 512 x 24 bit-plane image?
A | 768 KB |
B | 1 MB |
C | 1.5 MB |
D | 2 MB |
Question 28 Explanation:
In computer graphics, z-buffering, also known as depth buffering, is the management of image depth coordinates in 3D graphics, usually done in hardware, sometimes in software
In a 3d-rendering engine, when an object is projected on the screen, the depth (z-value) of a generated pixel in the projected screen image is stored in a buffer (the z-buffer or depth buffer).
A z-value is the measure of the perpendicular distance from a pixel on the projection plane to its corresponding 3d-coordinate on a polygon in world-space.
Z-buffer requires 2 type of buffers to be filled: Depth buffer and Frame buffer
The amount of memory required by depth buffer in terms of bits is 512 x 512 x 24 = 6291456
The amount of memory required by frame buffer in terms of bits is 512 x 512 x 24 = 6291456
Total memory is required is sum of both depth and frame buffer memories = 6291456 + 6291456 = 12582912 bits which is equivalent to 1.5 MB(1.5x1024x1024x8)
In a 3d-rendering engine, when an object is projected on the screen, the depth (z-value) of a generated pixel in the projected screen image is stored in a buffer (the z-buffer or depth buffer).
A z-value is the measure of the perpendicular distance from a pixel on the projection plane to its corresponding 3d-coordinate on a polygon in world-space.
Z-buffer requires 2 type of buffers to be filled: Depth buffer and Frame buffer
The amount of memory required by depth buffer in terms of bits is 512 x 512 x 24 = 6291456
The amount of memory required by frame buffer in terms of bits is 512 x 512 x 24 = 6291456
Total memory is required is sum of both depth and frame buffer memories = 6291456 + 6291456 = 12582912 bits which is equivalent to 1.5 MB(1.5x1024x1024x8)
Question 30 |
In which of the following shading models of polygons, the interpolation of intensity values is done along the scan line?
A | Gourard shading |
B | Phong shading |
C | Constant shading |
D | Flat shading |
Question 30 Explanation:
→Gouraud shading is an interpolation method used in computer graphics to produce continuous shading of surfaces represented by polygon meshes.
→In practice, Gouraud shading is most often used to achieve continuous lighting on triangle surfaces by computing the lighting at the corners of each triangle and linearly interpolating the resulting colours for each pixel covered by the triangle.
→Phong shading refers to an interpolation technique for surface shading in 3D computer graphics.
→'Constant shading','faceted shading' or 'flat shading' is the approach applies an illumination model once to determine a single intensity value that is then used to shade an entire polygon, and holding the value across the polygon to reconstruct the polygon's shade.
→In practice, Gouraud shading is most often used to achieve continuous lighting on triangle surfaces by computing the lighting at the corners of each triangle and linearly interpolating the resulting colours for each pixel covered by the triangle.
→Phong shading refers to an interpolation technique for surface shading in 3D computer graphics.
→'Constant shading','faceted shading' or 'flat shading' is the approach applies an illumination model once to determine a single intensity value that is then used to shade an entire polygon, and holding the value across the polygon to reconstruct the polygon's shade.
Question 31 |
In graphics, the number of vanishing points depends on
A | the number of axes cut by the projection plane |
B | the centre of projection |
C | the number of axes which are parallel to the projection plane |
D | the perspective projections of any set of parallel lines that are not parallel to the projection plane |
Question 31 Explanation:
→Projections of lines that are not parallel to the view plane (i.e. lines that are not perpendicular to the view plane normal) appear to meet at some point on the view plane.
→This point is called the vanishing point. A vanishing point corresponds to every set of parallel lines.
→This point is called the vanishing point. A vanishing point corresponds to every set of parallel lines.
Question 32 |
A system is having 8 M bytes of video memory for bit-mapped graphics with 64-bit colour. What is the maximum resolution it can support?
A | 800 x 600 |
B | 1024 x 768 |
C | 1280 x 1024 |
D | 1920 x 1440 |
Question 32 Explanation:
Explanation:
Given file size is 8M bytes= 8*1024**1024*8=83,88,608
From the options,
⦁ 800*600*8=34,80,000
⦁ 1024*768*8=62,91,456
⦁ 1280*1024*8=13,10,720
⦁ 1920*1440*8=22,118,400
From the above , option A and B are less than file size.
From that two , maximum one is option B.
Given file size is 8M bytes= 8*1024**1024*8=83,88,608
From the options,
⦁ 800*600*8=34,80,000
⦁ 1024*768*8=62,91,456
⦁ 1280*1024*8=13,10,720
⦁ 1920*1440*8=22,118,400
From the above , option A and B are less than file size.
From that two , maximum one is option B.
Question 33 |
Which of the following is true about the z-buffer algorithm?
A | It is a depth sort algorithm |
B | No limitation on total number of objects |
C | Comparisons of objects is done |
D | z-buffer is initialized to background colour at start of algorithm |
Question 33 Explanation:
The Z-buffer algorithm is a convenient algorithm for rendering images properly according to depth.
To begin with, a buffer containing the closest depth at each pixel location is created parallel to the image buffer. Each location in this depth buffer is initialized to negative infinity.
Since the algorithm processes objects one at a time, the total number of polygons in a picture can be arbitrarily large.
To begin with, a buffer containing the closest depth at each pixel location is created parallel to the image buffer. Each location in this depth buffer is initialized to negative infinity.
Since the algorithm processes objects one at a time, the total number of polygons in a picture can be arbitrarily large.
Question 34 |
A Steiner patch is
A | Biquadratic Bezier patch |
B | Bicubic patch |
C | Circular patch only |
D | Bilinear Bezier patch |
Question 34 Explanation:
Steiner patches are triangular surface patches for which the Cartesian coordinates of points on the patch are defined parametrically by quadratic polynomial functions of two variables. So these surfaces are formed from biquadratic Bezier patches.
Question 35 |
The term Phong associated with
A | Ray tracing |
B | shading |
C | Hidden line removal |
D | a game |
Question 35 Explanation:
Phong shading is a per-fragment color computation. The vertex shader provides the normal and position data as out variables to the fragment shader. The fragment shader then interpolates these variables and computes the color
Question 36 |
Given that a 22 inch monitor with an aspect ratio of 16:9 has a monitor of 1920x1080, what is the width of the monitor?
A | 22 inches |
B | 8:53 inches |
C | 10:79 inches |
D | 19:17 inches |
Question 36 Explanation:
Step-1: To check the ratio [width/height= 1920 /1080 ]
Step-2: Ratio: 16/9.
Step-3: Using Pythagoras theorem (9x) 2 +(16x) 2 =(22) 2
x=19.17 inch
Question 37 |
___ is a special effect in motion pictures and animations that changes one image or sharp into another through a seamless transition
A | Tweening |
B | Inverse kinematics |
C | Morphing |
D | Tweaking |
Question 37 Explanation:
Morphing is a special effect in motion pictures and animations that changes (or morphs) one image or shape into another through a seamless transition. morphing means stretching or as part of a fantasy or surreal sequence. Traditionally such a depiction would be achieved through cross-fading techniques on film.
Question 38 |
The easiest method in flash to draw a heptagon, is to use the___
A | Polystar tool with the "Polygon" style |
B | Polygon Tool |
C | Lasso Tool with the "create star" option |
D | Polystar Tool with the "star" style |
Question 38 Explanation:
There are 3 tools for drawing geometric shapes
1. Rectangle(Rectangle tool)
2. Oval(Oval tool)
3. Polygon(Polystar tool)
Note: We are not using Option A,C and D for drawing heptagon.
1. Rectangle(Rectangle tool)
2. Oval(Oval tool)
3. Polygon(Polystar tool)
Note: We are not using Option A,C and D for drawing heptagon.
Question 39 |
What is the bitrate for transmitting uncompressed 800x600 pixel color frame with 8 bits/pixel at 40 frames/Second?
A | 1536 Mbps |
B | 2.4 Mbps |
C | 15.36 Mbps |
D | 153.6 Mbps |
Question 39 Explanation:
Step-1: Given data, Uncompressed pixel = 800*600
Step-2: Each of 8 bit = 800*600 *8
Step-3: Bit rate for transmitting = 800*600 *8 *40 =153600000 bits
Step-4: Here, they are given in Mbps. 153600000 bits =153.6Mbps
Step-2: Each of 8 bit = 800*600 *8
Step-3: Bit rate for transmitting = 800*600 *8 *40 =153600000 bits
Step-4: Here, they are given in Mbps. 153600000 bits =153.6Mbps
Question 40 |
Anti aliasing is important to improve readability of text. It deals with the
A | Elimination of "jaggies" |
B | Spacing between two individual characters |
C | Underlining letters |
D | Spacing of a group of characters |
Question 40 Explanation:
● Antialiasing removes jagged edges by adding subtle color changes around the lines, tricking the human eye into thinking that the lines are not jagged.
● The slight changes in color around the edges of an image help the line blend around curves, giving the impression that the line is true.
● These color changes are made on a very small scale that the human eye cannot detect under normal circumstances. In order to be able to see that an image has been antialiased, it would have to be magnified.
● The slight changes in color around the edges of an image help the line blend around curves, giving the impression that the line is true.
● These color changes are made on a very small scale that the human eye cannot detect under normal circumstances. In order to be able to see that an image has been antialiased, it would have to be magnified.
Question 41 |
Which of the following is interactive?
A | A radio broadcast |
B | A talk show on TV |
C | A newspaper |
D | A computer game |
Question 41 Explanation:
Options A,B and C are not interactive , it will provide only information to the people. Where as Computer game in which computer user should interact with the computer in order to play the game
Question 42 |
The file size of a 640 by 480 pictures of 256 colours in a 8-bit resolution is
A | 300KB |
B | 900KB |
C | 128KB |
D | 1024KB |
Question 42 Explanation:
●Give picture size with 640 by 480 resolution with 256 colors per pixel.
●This implies 640 * 480 = 307,200 pixels. Recall that 256 values requires 8 bits of computer storage.
●Hence (307,200 pixels) * (8 bits per pixel) = 2,457,600 bits of storage.
●A common method for selling computer storage is in 8 bit groupings called bytes.
●Hence the picture would require (2,457,600 bits) / (8 bits per byte) = 307,200 bytes of computer storage.
●This implies 640 * 480 = 307,200 pixels. Recall that 256 values requires 8 bits of computer storage.
●Hence (307,200 pixels) * (8 bits per pixel) = 2,457,600 bits of storage.
●A common method for selling computer storage is in 8 bit groupings called bytes.
●Hence the picture would require (2,457,600 bits) / (8 bits per byte) = 307,200 bytes of computer storage.
Question 43 |
The process of producing bitmapped images from a view of 3-D models in a 3-D scene is called
A | Rendering |
B | Looping |
C | Cross dissolving |
D | Imaging |
Question 43 Explanation:
Rendering or image synthesis is the automatic process of generating a photorealistic or non-photorealistic image from a 2D or 3D model (or models in what collectively could be called a scene file) by means of computer programs.
Question 44 |
Even when the screen is completely dark while the film is in motion, commercial motion pictures use
A | 32 frames per second or 101 screen illuminations per second |
B | 72 frames per second or 234 screen illuminations per second |
C | 8 frames per second or 32 screen illuminations per second |
D | 24 frames per second or 72 screen illuminations per second |
Question 44 Explanation:
→ Motion picture, also called film or movie, series of still photographs on film, projected in rapid succession onto a screen by means of light.
→ When a motion picture film is projected on a screen at the rate of at least 16 illuminations per second but the commercial motion pictures uses 24 frames per second or 72 screen illuminations per second.
→ Film Technology standard is 24 frames per second, a three bladed shutter and some dreamy motion blur, all projected as shadow and light on the side of a wall.
→ When a motion picture film is projected on a screen at the rate of at least 16 illuminations per second but the commercial motion pictures uses 24 frames per second or 72 screen illuminations per second.
→ Film Technology standard is 24 frames per second, a three bladed shutter and some dreamy motion blur, all projected as shadow and light on the side of a wall.
Question 45 |
Which of the following is a special effect in motion pictures and animation that changes one image/picture into another through a seamless transition?
A | Modeling |
B | Morphing |
C | Animating |
D | Wrapping |
Question 45 Explanation:
→ Morphing is a special effect in motion pictures and animations that changes (or morphs) one image or shape into another through a seamless transition.
→ Morphing means stretching or as part of a fantasy or surreal sequence.
→ Morphing means stretching or as part of a fantasy or surreal sequence.
Question 46 |
In which of the following, the density of the core remains constant from the center to the edges?
A | Single mode fiber |
B | Multimedia step-index fiber |
C | Multimode graded index fiber |
D | Single mode step index fiber |
Question 46 Explanation:
Multimode Step-index: In multimode step-index fiber, the density of the core remains constant from the center to the edges. A beam of light moves through this constant density in a straight line until it reaches the interface of the core and the cladding
Question 47 |
MPEG involves both spatial compression and temporal compression. The spatial compression is similar to JPEG and temporal compression removes_____frames.
A | Voice |
B | Spatial |
C | Temporal |
D | Redundant |
Question 47 Explanation:
MPEG: The MPEG codec can only be used when the final video file will be in MPEG format (it is not compatible with other file types). It uses a lossy compression scheme (although it may be lossless at high-quality settings) and spatial and temporal compression. MPEG offers the best compression possible, but MPEGs are not yet as widely supported on the Web as other video formats.
Spatial compression:
Spatial (or intraframe) compression takes place on each individual frame of the video, compressing the pixel information as though it were a still image. JPEG, PNG and PICT files are an example of spatial compression.
It is known as the intraframe method.
Temporal compression:
It happens over a series of frames of the video. Temporal (or interframe) compression happens over a series of frames and takes advantage of areas of the image that remain unchanged from frame to frame, throwing out data for repeated pixels.
It is also called the interframe method.
Spatial compression:
Spatial (or intraframe) compression takes place on each individual frame of the video, compressing the pixel information as though it were a still image. JPEG, PNG and PICT files are an example of spatial compression.
It is known as the intraframe method.
Temporal compression:
It happens over a series of frames of the video. Temporal (or interframe) compression happens over a series of frames and takes advantage of areas of the image that remain unchanged from frame to frame, throwing out data for repeated pixels.
It is also called the interframe method.
Question 48 |
While making bubbled lists, which of the following options are available?
A | Square,disc,tringle |
B | Triangle,disc,circle |
C | Triangle,square,circle |
D | Disc,square,circle |
Question 48 Explanation:
→ Disc: A filled circle
→ Circle : An unfilled circle
→ square : A filled square
→ Circle : An unfilled circle
→ square : A filled square
Question 49 |
What is compression ratio in a typical mp3 audio files?
A | 4:1 |
B | 6:1 |
C | 8:1 |
D | 10:1 |
Question 49 Explanation:
→ Compression efficiency of encoders is typically defined by the bit rate, because compression ratio depends on the bit depth and sampling rate of the input signal.
→ They may use the Compact Disc (CD) parameters as references (44.1 kHz, 2 channels at 16 bits per channel or 2×16 bit), or sometimes the Digital Audio Tape (DAT) SP parameters (48 kHz, 2*16 bit)
→ 2 channels of 16-bit audio at 44.1KHz = 2*16* 44100
= 1411200 bits/sec
= 172 kbyte/sec
→ Compression ratio = 172/16
= 10.75 :1
= 11:1 (or) 10:1
→ They may use the Compact Disc (CD) parameters as references (44.1 kHz, 2 channels at 16 bits per channel or 2×16 bit), or sometimes the Digital Audio Tape (DAT) SP parameters (48 kHz, 2*16 bit)
→ 2 channels of 16-bit audio at 44.1KHz = 2*16* 44100
= 1411200 bits/sec
= 172 kbyte/sec
→ Compression ratio = 172/16
= 10.75 :1
= 11:1 (or) 10:1
Question 50 |
Which of the following compression algorithms is used to generate a .png file?
A | LZ78 |
B | Deflate |
C | LZW |
D | Huffman |
Question 50 Explanation:
→ Deflate is a lossless data compression algorithm and associated file format that uses a combination of the LZ77 algorithm and Huffman coding.
→ An algorithm producing Deflate files is widely thought to be implementable in a manner not covered by patents.
→ This has led to its widespread use, for example in gzip compressed files, PNG image files and the ZIP file format for which Katz originally designed it.
→ An algorithm producing Deflate files is widely thought to be implementable in a manner not covered by patents.
→ This has led to its widespread use, for example in gzip compressed files, PNG image files and the ZIP file format for which Katz originally designed it.
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