Bit-rate
Question 1 |
Assume that we need to download text documents at the rate of 100 pages per minute. A page is an average of 24 lines with 80 characters in each line and each character requires 8 bits. Then the required bit rate of the channel is _____.
1.636 Kbps | |
1.636 Mbps | |
3.272 Mbps | |
3.272 Kbps | |
None of the above |
Question 1 Explanation:
-- Number of Pages(P)=100 per Minute
-- Number of Lines(L)= 24
-- Number of characters(C) =80
-- One character(O) =8 bits
-- Bit rate of channel=?
Step-1: Bit rate of channel= P*L*C*O
-- Number of Lines(L)= 24
-- Number of characters(C) =80
-- One character(O) =8 bits
-- Bit rate of channel=?
Step-1: Bit rate of channel= P*L*C*O
Question 2 |
A multiplexer combines four 100-Kbps channels using a time slot of 2 bits. What is the bit rate?
100 Kbps | |
200 Kbps | |
400 Kbps | |
1000 Kbps |
Question 2 Explanation:
Frame duration= 1/50,000
= 20 sec
Frame size= No.of bits per frame
= 8 bits
Bit Rate= Frame Rate * No.of bits per frame
= 50000*8
= 400 kbps

= 20 sec
Frame size= No.of bits per frame
= 8 bits
Bit Rate= Frame Rate * No.of bits per frame
= 50000*8
= 400 kbps

There are 2 questions to complete.
