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August 17, 2023NIC-NIELIT Scientist-B 2020
August 18, 2023ISRO CS 2020
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Question 2
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A non-pipelined CPU has 12 general purpose registers(R0, R1, R2,……..R12). Following operations are supported
ADD Ra, Rb, Rr Add Ra to Rb and store the result in Rr
MUL Ra, Rb, Rr Multiply Ra to Rb and store the result in Rr
MUL operations takes two clock cycles, ADD takes one clock cycle.
Calculate the minimum number of clock cycles required to compute the value of the expression XY+XYZ+YZ. The variables X, Y, Z are initially available in registers R0, R1 and R2 contents of these registers must not be modified.
ADD Ra, Rb, Rr Add Ra to Rb and store the result in Rr
MUL Ra, Rb, Rr Multiply Ra to Rb and store the result in Rr
MUL operations takes two clock cycles, ADD takes one clock cycle.
Calculate the minimum number of clock cycles required to compute the value of the expression XY+XYZ+YZ. The variables X, Y, Z are initially available in registers R0, R1 and R2 contents of these registers must not be modified.
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5
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6
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7
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8
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Question 2 Explanation:
To calculate XY+XYZ+YZ, we need at least 3 multiplication operations and 2 ADD operations.
Assuming R0 = X, R1 = Y, R2 = Z.
MUL R3, R0, R1
MUL R4, R3, R2
ADD R5, R4, R3
MUL R6, R1, R2
ADD R7, R5, R6
Total we need 3 multiplication operations and 2 add operations.
Total cycles needed = 3*2+2 = 8
Correct Answer: D
Question 2 Explanation:
To calculate XY+XYZ+YZ, we need at least 3 multiplication operations and 2 ADD operations.
Assuming R0 = X, R1 = Y, R2 = Z.
MUL R3, R0, R1
MUL R4, R3, R2
ADD R5, R4, R3
MUL R6, R1, R2
ADD R7, R5, R6
Total we need 3 multiplication operations and 2 add operations.
Total cycles needed = 3*2+2 = 8
What is the correct answer since in the video explanation it’s different. And option is option B) 6 in the video
Yes. The correct answer is 6 only. Please follow video explanation.