...
Computer-Organization
October 5, 2023
NIC-NIELIT Scientist-B 2020
October 5, 2023
Computer-Organization
October 5, 2023
NIC-NIELIT Scientist-B 2020
October 5, 2023

Cache

Question 25

A cache line is 64 bytes. The main memory has latency 32 ns and bandwidth 1 GBytes/s. The time required to fetch the entire cache line from the main memory is

A
32 ns
B
64 ns
C
96 ns
D
128 ns
Question 25 Explanation: 
For 1GBytes/s bandwidth → it takes 1 sec to load 109 bytes on line.
→ So, for 64 bytes it will take 64*1/109 = 64ns.
Main memory latency = 32
Total time required to place cache line is
64+32 = 96 ns
Correct Answer: C
Question 25 Explanation: 
For 1GBytes/s bandwidth → it takes 1 sec to load 109 bytes on line.
→ So, for 64 bytes it will take 64*1/109 = 64ns.
Main memory latency = 32
Total time required to place cache line is
64+32 = 96 ns
0 0 votes
Article Rating
Subscribe
Notify of
0 Comments
Inline Feedbacks
View all comments
0
Would love your thoughts, please comment.x
()
x
error: Alert: Content selection is disabled!!