Operating-Systems
October 5, 2023Software-Engineering
October 5, 2023Operating-Systems
|
Question 14
|
Consider the following schedule S of transactions T1 and T2:
T1 T2
Read(A)
A = A - 10
Read (A)
Temp = 0.2*A
Write(A)
Read(B)
Write(A)
Read(B)
B = B + 10
Write(B)
B = B + Temp
Write(B)
Which of the following is TRUE about the schedule S?
|
S is serializable only as T1, T2
|
|
|
S is serializable only as T2, T1
|
|
|
S is serializable both as T1, T2 and T2, T1
|
|
|
S is serializable either as T1 or as T2
|
|
|
None of these
|
Question 14 Explanation:
The given statement is not serializable as cycle exist in precedence graph. Therefore, options A, B, C, D are not correct.
Correct Answer: E
Question 14 Explanation:
The given statement is not serializable as cycle exist in precedence graph. Therefore, options A, B, C, D are not correct.
Subscribe
Login
0 Comments