###### Algorithms

October 11, 2023###### UGC NET CS 2010 Dec-Paper-2

October 11, 2023# UGC NET CS 2010 Dec-Paper-2

Question 1 |

The number of integers between 1 and 250 that are divisible by 2, 5 and 7 is

2 | |

3 | |

5 | |

8 |

Question 1 Explanation:

Here, we have to find all possible integers between 250 which was divisible by 2,5 and 7.

Solving this problem by 2 methods:

1. Venn diagram

2. Mathematical substitution.

In this problem, we are using Mathematical substitution method.

Step-1: According to condition, we can perform least common multiple(LCM) of 2,5 and 7=70

Step-2: Total number of integers= ⌊250/70⌋

= 3

Note: Divisible numbers are 70,140 and 210.

Solving this problem by 2 methods:

1. Venn diagram

2. Mathematical substitution.

In this problem, we are using Mathematical substitution method.

Step-1: According to condition, we can perform least common multiple(LCM) of 2,5 and 7=70

Step-2: Total number of integers= ⌊250/70⌋

= 3

Note: Divisible numbers are 70,140 and 210.

Correct Answer: B

Question 1 Explanation:

Here, we have to find all possible integers between 250 which was divisible by 2,5 and 7.

Solving this problem by 2 methods:

1. Venn diagram

2. Mathematical substitution.

In this problem, we are using Mathematical substitution method.

Step-1: According to condition, we can perform least common multiple(LCM) of 2,5 and 7=70

Step-2: Total number of integers= ⌊250/70⌋

= 3

Note: Divisible numbers are 70,140 and 210.

Solving this problem by 2 methods:

1. Venn diagram

2. Mathematical substitution.

In this problem, we are using Mathematical substitution method.

Step-1: According to condition, we can perform least common multiple(LCM) of 2,5 and 7=70

Step-2: Total number of integers= ⌊250/70⌋

= 3

Note: Divisible numbers are 70,140 and 210.

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