Programming-for-Output-Problems
October 12, 2023Data-Structures
October 12, 2023GATE 2011
| Question 8 |
Let the page fault service time to 10 ms in a computer with average memory access time being 20 ns. If one page fault is generated for every 106 memory accesses, what is the effective access time for the memory?
| 21 ns | |
| 30 ns | |
| 23 ns | |
| 35 ns |
Question 8 Explanation:
P = page fault rate
EA = p × page fault service time
+ (1 – p) × Memory access time
= 1/106×10×10<sup6+(1-1/106)×20 ≅ 29.9 ns</sup
EA = p × page fault service time
+ (1 – p) × Memory access time
= 1/106×10×10<sup6+(1-1/106)×20 ≅ 29.9 ns</sup
Correct Answer: B
Question 8 Explanation:
P = page fault rate
EA = p × page fault service time
+ (1 – p) × Memory access time
= 1/106×10×10<sup6+(1-1/106)×20 ≅ 29.9 ns</sup
EA = p × page fault service time
+ (1 – p) × Memory access time
= 1/106×10×10<sup6+(1-1/106)×20 ≅ 29.9 ns</sup
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