###### GATE 1999

October 14, 2023###### Algorithms

October 14, 2023# Computer-Organization

Question 23 |

A micro instruction into be designed to specify

- (a) none or one of the three micro operations of one kind and

(b) none or upto six micro operations of another kind

The minimum number of bits in the micro-instruction is

9 | |

5 | |

8 | |

None of the above |

Question 23 Explanation:

(a) This is a vertical microprogramming because at any given time atmost one micro-operations will be activated.

So, no. of bits required

⌈log

(b) This is a horizontal micro-programming because at any given time atmost six micro-operations will be activated.

So, no. of bits required = 6

So, total minimum no. of bits required = 6+2 = 8

So, no. of bits required

⌈log

_{2}(3)⌉ = 2(b) This is a horizontal micro-programming because at any given time atmost six micro-operations will be activated.

So, no. of bits required = 6

So, total minimum no. of bits required = 6+2 = 8

Correct Answer: C

Question 23 Explanation:

(a) This is a vertical microprogramming because at any given time atmost one micro-operations will be activated.

So, no. of bits required

⌈log

(b) This is a horizontal micro-programming because at any given time atmost six micro-operations will be activated.

So, no. of bits required = 6

So, total minimum no. of bits required = 6+2 = 8

So, no. of bits required

⌈log

_{2}(3)⌉ = 2(b) This is a horizontal micro-programming because at any given time atmost six micro-operations will be activated.

So, no. of bits required = 6

So, total minimum no. of bits required = 6+2 = 8

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