Programming
October 18, 20232014 June UGC NET Paper 1
October 18, 2023GATE 2013
Question 6
|
Which one of the following is the tightest upper bound that represents the number of swaps required to sort n numbers using selection sort?
O(log n)
|
|
O(n)
|
|
O(n log n)
|
|
O(n2)
|
Question 6 Explanation:
Best, Average and worst case will take maximum O(n) swaps.
Selection sort time complexity O(n2) in terms of number of comparisons. Each of these scans requires one swap for n-1 elements (the final element is already in place).
Selection sort time complexity O(n2) in terms of number of comparisons. Each of these scans requires one swap for n-1 elements (the final element is already in place).
Correct Answer: B
Question 6 Explanation:
Best, Average and worst case will take maximum O(n) swaps.
Selection sort time complexity O(n2) in terms of number of comparisons. Each of these scans requires one swap for n-1 elements (the final element is already in place).
Selection sort time complexity O(n2) in terms of number of comparisons. Each of these scans requires one swap for n-1 elements (the final element is already in place).
Subscribe
Login
0 Comments