GATE 1994
October 25, 2023Research-Aptitude
October 25, 2023Nielit Scientist-B CS 22-07-2017
| Question 30 |
If each address space represents one byte of storage space, how many address lines are needed to access RAM chips arranged in a 4 x 6 array, where each chip is 8K x 4 bits?
| 13 | |
| 14 | |
| 16 | |
| 17 |
Question 30 Explanation:
Size of each Ram chip = 8K x 4 bits = 23 x 210x 22 ⇒ 215 bits = 212 bytes
Number of chips required = 6 x 4 = 24 = 5 bits
So, total number of bits required = 12 + 5 = 17 bits
Number of chips required = 6 x 4 = 24 = 5 bits
So, total number of bits required = 12 + 5 = 17 bits
Correct Answer: D
Question 30 Explanation:
Size of each Ram chip = 8K x 4 bits = 23 x 210x 22 ⇒ 215 bits = 212 bytes
Number of chips required = 6 x 4 = 24 = 5 bits
So, total number of bits required = 12 + 5 = 17 bits
Number of chips required = 6 x 4 = 24 = 5 bits
So, total number of bits required = 12 + 5 = 17 bits