ComputerOrganization
October 28, 2023GATE 1991
October 28, 2023ComputerOrganization
Question 21

The expression (a*b)* c op….
where ‘op’ is one of ‘+’, ‘*’ and ‘↑’ (exponentiation) can be evaluated on a CPU with a single register without storing the value of (a * b) if
‘op’ is ’+’ or ‘*’


‘op’ is ’↑’ or ‘*’


‘op’ is ’↑’ or ‘+’


not possible to evaluate without storing

Question 21 Explanation:
Lets say, the expression is one of the below:
(a*b)*c + d
(a*b)*c * d
(a*b)*c ∧ d
In any case, brackets has the highest priority always. So I have to compute brackets first. Now, for + and *, I can do the rest of the operation and save results in the same register. But for exponentiation, I have to store the result of a*b, then do the computation of c∧d, then multiply these two results.
Hence, (A) is correct.
(a*b)*c + d
(a*b)*c * d
(a*b)*c ∧ d
In any case, brackets has the highest priority always. So I have to compute brackets first. Now, for + and *, I can do the rest of the operation and save results in the same register. But for exponentiation, I have to store the result of a*b, then do the computation of c∧d, then multiply these two results.
Hence, (A) is correct.
Correct Answer: A
Question 21 Explanation:
Lets say, the expression is one of the below:
(a*b)*c + d
(a*b)*c * d
(a*b)*c ∧ d
In any case, brackets has the highest priority always. So I have to compute brackets first. Now, for + and *, I can do the rest of the operation and save results in the same register. But for exponentiation, I have to store the result of a*b, then do the computation of c∧d, then multiply these two results.
Hence, (A) is correct.
(a*b)*c + d
(a*b)*c * d
(a*b)*c ∧ d
In any case, brackets has the highest priority always. So I have to compute brackets first. Now, for + and *, I can do the rest of the operation and save results in the same register. But for exponentiation, I have to store the result of a*b, then do the computation of c∧d, then multiply these two results.
Hence, (A) is correct.
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