Operating-Systems
November 5, 2023NTA UGC NET JUNE-2023 Paper-2
November 5, 2023UGC NET CS 2018-DEC Paper-2
| Question 15 |
Consider the following set of processes and the length of CPU burst time given in milliseconds:
Assume that processes being scheduled with Round-Robin Scheduling Algorithm with Time Quantum 4ms. Then The waiting time for P4 is _________ ms.
Assume that processes being scheduled with Round-Robin Scheduling Algorithm with Time Quantum 4ms. Then The waiting time for P4 is _________ ms.
| 0 | |
| 4 | |
| 12 | |
| 6 |
Question 15 Explanation:
Waiting time = Turnaround time- Burst time
Turnaround time = Completion time – Arrival time.
Since in question Arrival time is not given so consider it as “0” for all the processes .
Turnaround time = Completion time – Arrival time.
Since in question Arrival time is not given so consider it as “0” for all the processes .
Correct Answer: C
Question 15 Explanation:
Waiting time = Turnaround time- Burst time
Turnaround time = Completion time – Arrival time.
Since in question Arrival time is not given so consider it as “0” for all the processes .
Turnaround time = Completion time – Arrival time.
Since in question Arrival time is not given so consider it as “0” for all the processes .