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Operating-Systems
November 5, 2023
NTA UGC NET JUNE-2023 Paper-2
November 5, 2023
Operating-Systems
November 5, 2023
NTA UGC NET JUNE-2023 Paper-2
November 5, 2023

Question 4882 – UGC NET CS 2018-DEC Paper-2

​Consider the following set of processes and the length of CPU burst time given in milliseconds:


Assume that processes being scheduled with Round-Robin Scheduling Algorithm with Time Quantum 4ms. Then The waiting time for P4 is _________ ms.

Correct Answer: C

Question 15 Explanation: 
Waiting time = Turnaround time- Burst time
Turnaround time = Completion time – Arrival time.
Since in question Arrival time is not given so consider it as “0” for all the processes .
A
0
B
4
C
12
D
6
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